I'm doing the "121. Best Time to Buy and Sell Stock" easy LeetCode problem but my output isn't correct and I can't figure out what I'm doing wrong. Here is the problem explanation:
You are given an array prices where prices[i] is the price of a given stock on the ith day.
You want to maximize your profit by choosing a single day to buy one stock and choosing a different day in the future to sell that stock.
Return the maximum profit you can achieve from this transaction. If you cannot achieve any profit, return 0.
Example 1:
Input: prices = [7,1,5,3,6,4]
Output: 5
Explanation: Buy on day 2 (price = 1) and sell on day 5 (price = 6), profit = 6-1 = 5.
Note that buying on day 2 and selling on day 1 is not allowed because you must buy before you sell.
Example 2:
Input: prices = [7,6,4,3,1]
Output: 0
Explanation: In this case, no transactions are done and the max profit = 0.
Here is what I've done so far:
class Solution {
public int maxProfit(int[] prices) {
int arrayLength = ((prices.length)*(prices.length + 1))/2;
int[] profits = new int[arrayLength];
int count = 0;
for (int i = (prices.length - 1); i >= 0; i--)
{
for (int x = i; x >= 0; x--)
{
profits[count] = prices[i] - prices[x];
count++;
}
}
int maximumProfit = profits[0];
for (int y = 1; y < profits.length; y++)
{
if (profits[y] > profits[y - 1])
maximumProfit = profits[y];
}
return maximumProfit;
}
}