Match valid email addresses that belong to a specific domain example.com, while also allowing for optional subdomains

Asked Sep 01 '23 at 05:26

Active Sep 01 '23 at 05:56

Viewed 27 times

import re

def validate_email(email):
    pattern = r'^(?:(?:[a-zA-Z0-9_-]+\.)*[a-zA-Z0-9_-]+@)?(?:[a-zA-Z0-9_-]+\.)?example\.com$'
    return re.match(pattern, email)

emails = [
    "john.doe@example.com",
    "jane.smith@subdomain.example.com",
    "user@gmail.com",
    "admin@subdomain.example.org",
]

for email in emails:
    if validate_email(email):
        print(f"{email} is a valid email.")
    else:
        print(f"{email} is NOT a valid email.")

In this code, the regular expression is designed to match email addresses that belong to the domain example.com and can include optional subdomains. It should handle variations like user@example.com, user@sub.example.com, and user@sub.sub.example.com. but its not working as expected

asked Sep 01 '23 at 05:26

prabu naresh

Would this be sufficient? `.+?@(?:.+?example\.com$|example\.com)` – Cow Sep 01 '23 at 05:32
`[\w.]+@(?:\w+\.)?example\.com` – CAustin Sep 01 '23 at 05:33
@Cow That wouldn't be an expected pattern if we're just talking about typical subdomains. – CAustin Sep 01 '23 at 05:35
2

You might be best off using a specialised email address parser, and then greping to find the URL after the @ sign. Email addresses are stranger than you could possibly imagine – Mark Sep 01 '23 at 05:36
See: https://www.netmeister.org/blog/email.html – Mark Sep 01 '23 at 05:37
2

@Cow Ah, I was just looking at the examples in the code. In that case, you can use `[\w.]+@(?:[\w.]+)?example\.com` – CAustin Sep 01 '23 at 05:37
@CAustin You should make an answer – Cow Sep 01 '23 at 05:41

Match valid email addresses that belong to a specific domain example.com, while also allowing for optional subdomains

0 Answers0