can someone explaine to me why foo isnt alerted as 10?`
var foo = 1;
function bar() {
foo = 10;
return;
function foo() {}
}
bar();
alert(foo);I tried to console.log foo outside bar in order to see if foo has change and it was foo=10.
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Your `function foo() {}` inside of the `bar` function, creates a local variable by that name inside `bar`. So the `foo` you are afterwards (why after? see duplicate) changing in there, is not the same `foo` as the global one outside the function. – CBroe Sep 01 '23 at 06:08
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but i change the glioal foo before i decler the foo function... – אוסנת דיין Sep 01 '23 at 06:55
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1Let me repeat: _"(why after? see duplicate) "_ – CBroe Sep 01 '23 at 06:58
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ok thanks!!!!!! – אוסנת דיין Sep 01 '23 at 12:58