C++: Define a function which takes a member class of a templated class

Question

I have the following class:

template<int p, int q, int r>
struct ga { // geometric algebra with signature (p,q,r)
  static const int d = p+q+r;
  
  struct mv { ... }; // multivector in this GA
  
  template<int g>
  struct gmv : mv { ... }; // multivector in this GA with grade g
};

And I want to make a function outside of this class that takes a ga::mva

template<int p, int q, int r>
void print(ga<p,q,r>::mv) { ... }

However this gives the following error message:

error: variable or field 'print' declared void
void print(ga<p,q,r>::mv v) {
     ^~~~~

error: expected ')' before 'v'
void print(ga<p,q,r>::mv v) {
          ~             ^~
                        )

These error messages seem weird to me and suggests the compiler is not properly parsing my code.

I also tried

template<int p,int q,int r, ga<p,q,r> g>
void print(g::mv v) { ... }

Giving the declared void error and also

error: 'g' is not a class, namespace, or enumeration

It works if I do

using pga = ga<3,1,0>
void print(pga::mv v) { ... }

So how can I implement the general version?

Edit: Full MRE

template<int p, int q, int r>
struct ga { // geometric algebra with signature (p,q,r)
  static const int d = p+q+r;
  
  struct mv {}; // multivector in this GA
  
  template<int g>
  struct gmv : mv {}; // multivector in this GA with grade g
};

template<int p, int q, int r>
void print(typename ga<p,q,r>::mv v) {}

int main() {
  using pga = ga<3,1,0>;
  pga::gmv<2> v;
  print(v);
}