JSON formatting

Question

Using the method found here, I am collecting form values and posting them using the following code:

$.ajax({
    type: "POST",
    url: "http://"+document.domain+"/SimplaAdmin/includes/rpc.php",
    data: { data:postdata, method: 'addSite'},
    dataType: "json",
.......

Posted data is:

data:{
    "textfield": ["",""],
    "dropdown": ["option1","option1"],
    "siteTitle":"this is the site title",
    "siteKey":"",
    "siteurl":"",
    "address1":"",
    "address2":"",
    "address3":"",
    "landline":"",
    "method":"addSite",
    "small-input":"",
    "medium-input":"",
    "large-input":""
}

Then I try to get the value siteTitle using:

$data = $_POST['data'];
$obj=json_decode($data) ;
$title = $obj->{'siteTitle'};

But it does not work, where is the flaw in my thinking?

try json.stringify - Google-ify it ;) – PhD Oct 13 '11 at 00:16 — PhD, Oct 13 '11 at 00:16

score 1 · Answer 1 · answered Oct 13 '11 at 00:18

1

Your syntax is incorrect- You just need $title = $obj->siteTitle;

Also, I presume you added data: to the start of your JSON string for the purpose of this post? That also shouldn't be there.

Take for example:

<?php 

$string = '{"textfield":["",""],"dropdown":["option1","option1"],"siteTitle":"this is the site title","siteKey":"","siteurl":"","address1":"","address2":"","address3":"","landline":"","method":"addSite","small-input":"","medium-input":"","large-input":""}';

$obj = json_decode($string); 

print_r( $obj->siteTitle );

?>

Which outputs

this is the site title

answered Oct 13 '11 at 00:18

Ben Swinburne

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This returns null. data: is just what I grab from chrome, to show what is posted, it isn't there. – maxum Oct 13 '11 at 08:02
Have you tried print_r( $obj ); to see if it's actually decoding the string properly? – Ben Swinburne Oct 13 '11 at 08:15
Perhaps try removing `data:` from `data: { data:postdata, method: 'addSite'},` so it looks like this `data: { postdata, method: 'addSite'},` – Ben Swinburne Oct 13 '11 at 08:17
yep just did that, it's escaped! ala json post. Did a stripslashes($data) prior to the decode and now it works. – maxum Oct 13 '11 at 08:19
Nice one. Glad you've got it sorted. – Ben Swinburne Oct 13 '11 at 09:00

score 0 · Accepted Answer · answered Oct 18 '11 at 19:15

0

JSON was escaping the POST. Removed slashes and it worked.

answered Oct 18 '11 at 19:15

maxum

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score -1 · Answer 3 · answered Oct 13 '11 at 00:15

-1

Change $title = $obj->{'siteTitle'} to

$title = $obj['siteTitle'];

answered Oct 13 '11 at 00:15

max_

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It's not an array though. You need to pass a second argument with `TRUE` if you want an array returned. – alex Oct 13 '11 at 00:19
This will not work as by default `json_decode` returns an object. This will result in a Fatal error: Cannot use object of type stdClass as array error – Ben Swinburne Oct 13 '11 at 00:21

JSON formatting

3 Answers3

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