Phone number format in Javascript

Question

I need to check Format Phone Number.

+33xxxxxxxxx

0033xxxxxxxxx

EDIT : 0xxxxxxxxx

How can I do that with(out) regex ?

Probably the best library for dealing with phone numbers: http://code.google.com/p/libphonenumber/ — James Allardice, Oct 13 '11 at 15:25
I don't think it should. It's not a complete answer, it's just a useful reference. — James Allardice, Oct 13 '11 at 15:46

score 2 · Answer 1 · answered Oct 13 '11 at 15:44

2

The regex to match it would be this

(0033|\+33|0)?\d{9}

I use http://regexpal.com/ for quick regex testing

answered Oct 13 '11 at 15:44

pakopa

633
5
8

score 1 · Answer 2 · answered Apr 19 '12 at 23:39

PhoneFormat.com has a javascript library that has some formatting functions that you could easily drop into your project. It will take whatever number you throw at it and try and convert it to e164 (+ 33252525252), and also format it (+33 2 52 52 52 52)

Tim Pietzcker · Accepted Answer · 2011-10-13T15:42:05.427

1

if (/^(?:(?:\+|00)33|0)\d{9}$/.test(subject)) {
    // Successful match
} else {
    // Match attempt failed
}

edited Oct 13 '11 at 15:42

answered Oct 13 '11 at 15:33

Tim Pietzcker

328,213
58
503
561

Oh !!! Great, but If I need to change `33` by `261` or one other value ? What is the code ? – Steffi Oct 13 '11 at 15:36
If you still expect 9 digits after the country code, then just substitute `261` for `33`. And if you want to allow both, use `(?:216|33)` instead of `33`. – Tim Pietzcker Oct 13 '11 at 15:38
Yes, but if it a random value ? – Steffi Oct 13 '11 at 15:39
If it's random, what are you trying to validate it for? I think you need to go back and think about this, and write down *exactly* what you do and do not want to match. – Tim Pietzcker Oct 13 '11 at 15:40
All values between 01 and 300 – Steffi Oct 13 '11 at 15:43
`if (/^(?:(?:\+|00)33|0)\d{9}$/.test(subject))` : PERFECT – Steffi Oct 13 '11 at 15:45

TimWolla · Answer 4 · 2013-06-21T18:19:10.347

1

Try this regex: /^((\+|00)\d{2})?\d{9}$/

This matches each of your given cases (+YYXXXXXXXXX, 00YYXXXXXXXXX, XXXXXXXXX).

Edit: To match your edit: /^((\+|00)\d{2}|0)\d{9}$/

edited Jun 21 '13 at 18:19

answered Oct 13 '11 at 15:35

TimWolla

31,849
8
63
96

Adilson de Almeida Jr · Answer 5 · 2011-10-13T15:41:34.433

0

This is a regex that validates your examples:

/(\+|(00)|0)[0-9]{11}/.test(stringToTest)

edited Oct 13 '11 at 15:41

answered Oct 13 '11 at 15:34

Adilson de Almeida Jr

2,761
21
37

But it also validates 12345678901. – Tim Pietzcker Oct 13 '11 at 15:38

Phone number format in Javascript

5 Answers5

Linked