PHP - Get image url from RSS feed

Question

I have to get the url (not the link) of an image that I'm getting from an rss feed in PHP. I know that if I want to get the link (not url) of one of the feed titles I have to use $feed->channel->item->link; but what if I want to get the image url (not the link) of the feed item and insert it into a variable for later use? maybe $feed->channel->image->url; - i used this but nothing works.

This is what I used to get the feed.

function get_google_image($image){
{        $intento=0;
         $imagealt=get_the_title(); //its wordpress
         $image=get_the_title();
                 $words = explode(" ", $image);
                 $imagetitle = implode(" ", array_splice($words, 0, 2));
                 $image = implode(" ", array_splice($words, 0, 2));
         $image=str_replace(" ","+",$image);
         while (!$feed=simplexml_load_file("http://obsrv.com/General/ImageFeed.aspx?'$image'")){
                 $attempt+=1;
                 if ($attempt>5) break;
                 print "Retry".$attempt."<br>";
                 }
                 $imagelink=$feed->channel->image->url; //Here is the problem, this variable finally gets empty and i want it to be the url of the image so i can post it with html later in the line below
                 echo '<img title="' . $imagetitle . '" alt="' . $imagealt . '" src="' . $imagelink . '"/>';
}}

The feed is http://obsrv.com/General/ImageFeed.aspx? (here the variable with the keyword for the image search) I want to get the first item from the rss feed list (the first image because every rss post has a only one image and also has a this image as an file attached to the post if it that helps you to help me). So I want to get this image and take out the url into a variable so then I can make a html code for posting an image.

echo '<img title="' . $imagetitle . '" alt="' . $imagealt . '" src="' . $imagelink . '"/>';

Answer 1

You several issue in your code:

1. From the help page, I can see that you supplied the wrong URL structure:

   "http://obsrv.com/General/ImageFeed.aspx?'$image'"
   

   It should be:

   "http://obsrv.com/General/ImageFeed.aspx?q=" . $image . ""
   

2. I think there's bug in your code:

   First, you set $image as function parameter to get_google_image($image) And then you set $image taken from wordpress's function. I don't know if this is your intended method.

3. This code is also buggy:

   $image=str_replace(" ","+",$image);
   

   I think this is what you looking for:

   $image = urlencode($image);
   

4. Another issue is, you supplied simplexml_load_file() with URL.

   UPDATE: Phil pointed out that simplexml_load_file() does work with URL, if fopen HTTP wrapper is enabled. But, if it's disable, you can use this code as a workaround:

   $raw_html = file_get_contents( "http://obsrv.com/General/ImageFeed.aspx?q=$image" );
   $feed=simplexml_load_string( $raw_html );