How to find indexOf element in jQuery array?

Question

I have two selectors

    var allNodes = $("a.historyEntry");
    var errorNodes = $("a.historyEntry.error");

I would like to to find a node before first error node, so I need to find an index of first error node, how to do it?

I tried to use inArray method, but it doesn't work for this

$.inArray(allNodes, errorNodes.first())

or

$.inArray(allNodes, $(errorNodes.first()))

Is there any fast way to do it in jQuery or do I have to use for loop?

If I understand you correctly: some of the nodes in `allNodes` have the `error` class, and you want to find the last "good" node before the first "error" node. Is that right? — Blazemonger, Oct 14 '11 at 13:32

score 10 · Accepted Answer · answered Oct 14 '11 at 13:31

10

It's like indexOf... but just without the Of... it returns the index of the element if it exists, and -1 if it doesn't.

answered Oct 14 '11 at 13:31

Matt

score 2 · Answer 2 · answered Oct 14 '11 at 13:34

2

Use index(). It does exactly the same thing as indexOf in java.

answered Oct 14 '11 at 13:34

fireshadow52

score 2 · Answer 3 · answered Oct 14 '11 at 13:34

2

$.inArray value is the first parameter then the array:

$.inArray(allNodes, errorNodes.first())

should be:

$.inArray(errorNodes.first(), allNodes)

answered Oct 14 '11 at 13:34

Joe

3 Answers3