Get all child views inside LinearLayout at once

Question

I have a LinearLayout, which contains several child TextViews. How can I get child views of that LinerLayout using a loop?

score 310 · Accepted Answer · edited Jun 04 '17 at 16:53

310

Use getChildCount() and getChildAt(int index).

Example:

LinearLayout ll = …
final int childCount = ll.getChildCount();
for (int i = 0; i < childCount; i++) {
      View v = ll.getChildAt(i);
      // Do something with v.
      // …
}

edited Jun 04 '17 at 16:53

Benny

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answered Oct 16 '11 at 13:07

Yashwanth Kumar

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Hi Yashwanth Kumar, can i get all TextViews in that Linearlayout? – Hai nguyen Dec 18 '13 at 09:22
15

@hai-nguyen: You can use if (v instanceof TextView) {...} for that. – Anoop Apr 04 '14 at 10:54
3

what if one of the child is a ViewGroup and we want to get all those childs as well? – Hendra Anggrian Jul 25 '16 at 00:49
How can i get total no of `buttons` added in linear layout and devide it by *2* ? My purpose is to show 2 rows of buttons using *linear layout*. – Jay Rathod Dec 01 '16 at 08:39

score 49 · Answer 2 · edited May 10 '20 at 09:36

49

((ViewGroup) findViewById(android.R.id.content));// you can use this in an Activity to get your layout root view, then pass it to findAllEdittexts() method below.

Here I am iterating only EdiTexts, if you want all Views you can replace EditText with View.

SparseArray<EditText> array = new SparseArray<EditText>();

private void findAllEdittexts(ViewGroup viewGroup) {

    int count = viewGroup.getChildCount();
    for (int i = 0; i < count; i++) {
        View view = viewGroup.getChildAt(i);
        if (view instanceof ViewGroup)
            findAllEdittexts((ViewGroup) view);
        else if (view instanceof EditText) {
            EditText edittext = (EditText) view;
            array.put(editText.getId(), editText);
        }
    }
}

edited May 10 '20 at 09:36

jeprubio

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answered Dec 02 '14 at 12:39

Favas Kv

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Just to clarify, doing it recursively is because `getChildAt` returns only direct children – YoussefDir May 10 '20 at 06:42
Wouldn't it cause a stackoverflow error if we call "too" recursively? – FEBRYAN ASA PERDANA Aug 02 '21 at 21:30

Malwinder Singh · Answer 3 · 2020-05-04T08:33:45.963

10

It is easier with Kotlin using for-in loop:

for (childView in ll.children) {
     //childView is a child of ll         
}

Here ll is id of LinearLayout defined in layout XML.

edited May 04 '20 at 08:33

answered May 31 '19 at 10:28

Malwinder Singh

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score 8 · Answer 4 · answered Jun 23 '17 at 11:59

use this

    final int childCount = mainL.getChildCount();
    for (int i = 0; i < childCount; i++) {
          View element = mainL.getChildAt(i);

        // EditText
        if (element instanceof EditText) {
            EditText editText = (EditText)element;
            System.out.println("ELEMENTS EditText getId=>"+editText.getId()+ " getTag=>"+element.getTag()+
            " getText=>"+editText.getText());
        }

        // CheckBox
        if (element instanceof CheckBox) {
            CheckBox checkBox = (CheckBox)element;
            System.out.println("ELEMENTS CheckBox getId=>"+checkBox.getId()+ " getTag=>"+checkBox.getTag()+
            " getText=>"+checkBox.getText()+" isChecked=>"+checkBox.isChecked());
        }

        // DatePicker
        if (element instanceof DatePicker) {
            DatePicker datePicker = (DatePicker)element;
            System.out.println("ELEMENTS DatePicker getId=>"+datePicker.getId()+ " getTag=>"+datePicker.getTag()+
            " getDayOfMonth=>"+datePicker.getDayOfMonth());
        }

        // Spinner
        if (element instanceof Spinner) {
            Spinner spinner = (Spinner)element;
            System.out.println("ELEMENTS Spinner getId=>"+spinner.getId()+ " getTag=>"+spinner.getTag()+
            " getSelectedItemId=>"+spinner.getSelectedItemId()+
            " getSelectedItemPosition=>"+spinner.getSelectedItemPosition()+
            " getTag(key)=>"+spinner.getTag(spinner.getSelectedItemPosition()));
        }

    }

score 1 · Answer 5 · answered Nov 20 '19 at 03:14

Get all views from any type of layout

public List<View> getAllViews(ViewGroup layout){
        List<View> views = new ArrayList<>();
        for(int i =0; i< layout.getChildCount(); i++){
            views.add(layout.getChildAt(i));
        }
        return views;
}

Get all TextView from any type of layout

public List<TextView> getAllTextViews(ViewGroup layout){
        List<TextView> views = new ArrayList<>();
        for(int i =0; i< layout.getChildCount(); i++){
            View v =layout.getChildAt(i);
            if(v instanceof TextView){
                views.add((TextView)v);
            }
        }
        return views;
}

score -1 · Answer 6 · answered Jun 07 '19 at 10:30

Get all views of a view plus its children recursively in Kotlin:

private fun View.getAllViews(): List<View> {
    if (this !is ViewGroup || childCount == 0) return listOf(this)

    return children
            .toList()
            .flatMap { it.getAllViews() }
            .plus(this as View)
}

Get all child views inside LinearLayout at once

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