Java open stream from an arbitrary location in file

Question

I want to get a Stream from some arbitrary position in an existing file, for example I need to read/write from/to a file starting with 101th byte. Is it safe to use something like that?

final FileInputStream fin = new FileInputStream(f);
fin.skip(100);

Skip javadoc tells that it may sometimes skip lesser number of bytes than specified. What should I do then?

jtahlborn · Answer 1 · 2011-10-18T16:23:55.303

3

you can't write using a FileInputStream. you need to use a RandomAccessFile if you want to write to arbitrary locations in a file. ~~eunfortunately, there is no easy way to use a RandomAccessFile as an InputStream/OutputStream~~ (looks like @aix may have a good suggestion for adapting RandomAccessFile to InputStream/OutputStream), but there are various example adapters available online.

another alternative is to use a FileChannel. you can set the position of the FileChannel directly, then use the Channels utility methods to get InputStream/OutputStream adapters on top of the Channel.

edited Oct 18 '11 at 16:23

answered Oct 18 '11 at 15:58

jtahlborn

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Thanks for pointing me into the direction of RandomAccessFile. Eventually RandomAccessFile was all I needed, but @aix has given the exact answer I've been looking for. – Vic Oct 19 '11 at 09:08

score 1 · Accepted Answer · answered Oct 18 '11 at 16:17

1

How about the following:

final RandomAccessFile raf = new RandomAccessFile(f, mode);
raf.seek(100);
final FileInputStream fin = new FileInputStream(raf.getFD());
// read from fin

answered Oct 18 '11 at 16:17

NPE

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Java open stream from an arbitrary location in file

2 Answers2