milliseconds to days

Question

i did some research, but still can't find how to get the days... Here is what I got:

int seconds = (int) (milliseconds / 1000) % 60 ;
int minutes = (int) ((milliseconds / (1000*60)) % 60);
int hours   = (int) ((milliseconds / (1000*60*60)) % 24);
int days = ????? ;

Please help, I suck at math, thank's.

from [wikipedia](http://en.wikipedia.org/wiki/Millisecond#Examples): 86,400,000 (24×60×60×10×10×10) milliseconds — one day — amit, Oct 19 '11 at 23:49

whaley · Answer 1 · 2016-06-08T22:58:53.307

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For simple cases like this, TimeUnit should be used. TimeUnit usage is a bit more explicit about what is being represented and is also much easier to read and write when compared to doing all of the arithmetic calculations explicitly. For example, to calculate the number days from milliseconds, the following statement would work:

    long days = TimeUnit.MILLISECONDS.toDays(milliseconds);

For cases more advanced, where more finely grained durations need to be represented in the context of working with time, an all encompassing and modern date/time API should be used. For JDK8+, java.time is now included (here are the tutorials and javadocs). For earlier versions of Java joda-time is a solid alternative.

edited Jun 08 '16 at 22:58

answered Oct 19 '11 at 23:57

whaley

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If you are using Android this requires API level 9 – fernandohur May 15 '14 at 16:26
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TimeUnit will not round correctly. So 129600000l, which is 1.5 days, will return 1, not 2. – katsharp Mar 30 '16 at 11:25
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@katsharp that probably depends on what the correct definition of rounding is for for the specific case. My original answer only meant to address the simple cases in the original question. For more complex cases, such as accurately representing 1.5 days, I suggest using java.time from JDK8+ or joda-time if you are on an older java version. I'll amend my answer to suggest that. – whaley Apr 06 '16 at 16:48

Mark Byers · Accepted Answer · 2012-11-21T10:10:26.513

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If you don't have another time interval bigger than days:

int days = (int) (milliseconds / (1000*60*60*24));

If you have weeks too:

int days = (int) ((milliseconds / (1000*60*60*24)) % 7);
int weeks = (int) (milliseconds / (1000*60*60*24*7));

It's probably best to avoid using months and years if possible, as they don't have a well-defined fixed length. Strictly speaking neither do days: daylight saving means that days can have a length that is not 24 hours.

edited Nov 21 '12 at 10:10

answered Oct 19 '11 at 23:47

Mark Byers

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Don't forget about daylight savings changes – Mark Rotteveel Oct 20 '11 at 14:12
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@MarkRotteveel Some 10 years after your essential comment I posted [an answer that takes daylight saving time into account](https://stackoverflow.com/a/66847925/5772882). – Ole V.V. Mar 29 '21 at 02:26
The second option is working for days and weeks. Thanks. – Surendar D May 11 '23 at 06:47

score 4 · Answer 3 · answered Mar 05 '21 at 07:14

Go for TImeUnit in java

In order to import use, java.util.concurrent.TimeUnit

long millisec=System.currentTimeMillis();
long seconds=TimeUnit.MILLISECONDS.toSeconds(millisec);
long minutes=TimeUnit.MILLISECONDS.toMinutes(millisec);
long hours=TimeUnit.MILLISECONDS.toMinutes(millisec);
long days=TimeUnit.MILLISECONDS.toDays(millisec);

score 4 · Answer 4 · answered Mar 28 '21 at 18:20

java.time

You can use java.time.Duration which is modelled on ISO-8601 standards and was introduced with Java-8 as part of JSR-310 implementation. With Java-9 some more convenient methods were introduced.

Demo:

import java.time.Duration;

public class Main {
    public static void main(String[] args) {
        // Duration between the two instants
        Duration duration = Duration.ofMillis(1234567890L);

        // Print Duration#toString
        System.out.println(duration);

        // Custom format
        // ####################################Java-8####################################
        String formattedElapsedTime = String.format(
                "%d Day %02d Hour %02d Minute %02d Second %d Millisecond (%d Nanosecond)", duration.toDays(),
                duration.toHours() % 24, duration.toMinutes() % 60, duration.toSeconds() % 60,
                duration.toMillis() % 1000, duration.toNanos() % 1000000000L);
        System.out.println(formattedElapsedTime);
        // ##############################################################################

        // ####################################Java-9####################################
        formattedElapsedTime = String.format("%d Day %02d Hour %02d Minute %02d Second %d Millisecond (%d Nanosecond)",
                duration.toDaysPart(), duration.toHoursPart(), duration.toMinutesPart(), duration.toSecondsPart(),
                duration.toMillisPart(), duration.toNanosPart());
        System.out.println(formattedElapsedTime);
        // ##############################################################################
    }
}

A sample run:

PT342H56M7.89S
14 Day 06 Hour 56 Minute 07 Second 890 Millisecond (890000000 Nanosecond)
14 Day 06 Hour 56 Minute 07 Second 890 Millisecond (890000000 Nanosecond)

Learn more about the modern date-time API from Trail: Date Time.

score 2 · Answer 5 · answered Jan 06 '16 at 19:12

public static final long SECOND_IN_MILLIS = 1000;
public static final long MINUTE_IN_MILLIS = SECOND_IN_MILLIS * 60;
public static final long HOUR_IN_MILLIS = MINUTE_IN_MILLIS * 60;
public static final long DAY_IN_MILLIS = HOUR_IN_MILLIS * 24;
public static final long WEEK_IN_MILLIS = DAY_IN_MILLIS * 7;

You could cast int but I would recommend using long.

Ole V.V. · Answer 6 · 2021-03-29T02:14:17.997

You can’t. Sorry. Or more precisely: you can if you know a time zone and a start time (or end time). A day may have a length of 23, 24 or 25 hours or some other length. So there isn’t any sure-fire formula for converting from milliseconds to days. So while you can safely rely on 1000 milliseconds in a second, 60 seconds in a minute (reservation below) and 60 minutes in an hour, the conversion to days needs more context in order to be sure and accurate.

Reservation: In real life a minute is occasionally 61 seconds because of a leap second. Not in Java. Java always counts a minute as 60 seconds because common computer clocks don’t know leap seconds. Common operating systems and Java itself do know not only summer time (DST) but also many other timeline anomalies that cause a day to be shorter or longer than 24 hours.

To demonstrate. I am writing this on March 29, 2021, the day after my time zone, Europe/Copenhagen, and the rest of the EU switched to summer time.

    ZoneId myTimeZone = ZoneId.of("Europe/Copenhagen");
    ZonedDateTime now = ZonedDateTime.now(myTimeZone);
    ZonedDateTime twoDaysAgo = now.minusDays(2);
    ZonedDateTime inTwoDays = now.plusDays(2);
    
    System.out.println(ChronoUnit.MILLIS.between(twoDaysAgo, now));
    System.out.println(ChronoUnit.MILLIS.between(now, inTwoDays));

Output:

169200000
172800000

So how many milliseconds are in two days depends on which two days you mean. And in which time zone.

So what to do?

If for your purpose you can safely define a day as 24 hours always, for example because your days are counted in UTC or your users are fine with the inaccuracy, use either Duration or TimeUnit. Since Java 9 the Duration class will additionally tell you how many hours, minutes and seconds there are in addition to the whole days. See the answer by Arvind Kumar Avinash. For the TimeUnit enum see the answers by whaley and Dev Parzival. In any case the good news is that it doesn’t matter if you suck at math because the math is taken care of for you.

If you know a time zone and a starting point, use ZonedDateTime and ChronoUnit.DAYS. In this case too the math is taken care of for you.

ZonedDateTime start = LocalDate.of(2021, Month.MARCH, 28).atStartOfDay(myTimeZone);
long millisToConvert = 170_000_000;

ZonedDateTime end = start.plus(millisToConvert, ChronoUnit.MILLIS);
long days = ChronoUnit.DAYS.between(start, end);
System.out.format("%d days%n", days);

2 days

If you additionally want the hours, minutes and seconds:

    Duration remainingTime = Duration.between(start.plusDays(days), end);
    System.out.format(" - and an additional %s hours %d minutes %d seconds%n",
            remainingTime.toHours(),
            remainingTime.toMinutesPart(),
            remainingTime.toSecondsPart());

 - and an additional 0 hours 13 minutes 20 seconds

If instead you had got an endpoint, subtract your milliseconds from the endpoint using the minus method (instead of the plus method used in the above code) to get the start point.

Under no circumstances do the math yourself as in the question and in the currently accepted answer. It’s error-prone and results in code that is hard to read. And if your reader sucks at math, he or she can spend much precious developer time trying to verify that you have done it correctly. Leave the math to proven library methods, and it will be much easier for your reader to trust that your code is correct.

score 2 · Answer 7 · edited Jul 30 '12 at 22:31

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int days = (int) (milliseconds / 86 400 000 )

edited Jul 30 '12 at 22:31

Luke

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answered Oct 19 '11 at 23:48

Kurtis Nusbaum

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Zon · Answer 8 · 2019-01-11T08:41:20.660

In case you solve a more complex task of logging execution statistics in your code:

public void logExecutionMillis(LocalDateTime start, String callerMethodName) {

  LocalDateTime end = getNow();
  long difference = Duration.between(start, end).toMillis();

  Logger logger = LoggerFactory.getLogger(ProfilerInterceptor.class);

  long millisInDay = 1000 * 60 * 60 * 24;
  long millisInHour = 1000 * 60 * 60;
  long millisInMinute = 1000 * 60;
  long millisInSecond = 1000;

  long days = difference / millisInDay;
  long daysDivisionResidueMillis = difference - days * millisInDay;

  long hours = daysDivisionResidueMillis / millisInHour;
  long hoursDivisionResidueMillis = daysDivisionResidueMillis - hours * millisInHour;

  long minutes = hoursDivisionResidueMillis / millisInMinute;
  long minutesDivisionResidueMillis = hoursDivisionResidueMillis - minutes * millisInMinute;

  long seconds = minutesDivisionResidueMillis / millisInSecond;
  long secondsDivisionResidueMillis = minutesDivisionResidueMillis - seconds * millisInSecond;

  logger.info(
      "\n************************************************************************\n"
          + callerMethodName
          + "() - "
          + difference
          + " millis ("
          + days
          + " d. "
          + hours
          + " h. "
          + minutes
          + " min. "
          + seconds
          + " sec."
          + secondsDivisionResidueMillis
          + " millis).");
}

P.S. Logger can be replaced with simple System.out.println() if you like.

milliseconds to days

8 Answers8

java.time

Linked