Is there difference for Integer.MAX_VALUE between 32bit JVM and 64bit JVM?

Question

Is the value of Integer.MAX_VALUE different between 32bit JVMs and 64bit JVMs?

I am compiling a Java class using 32bit JDK and deploy it on a 64bit machine. I just want to make sure that I can rely on detecting if (aNumber == Integer.MAX_VALUE).

score 14 · Accepted Answer · answered Oct 21 '11 at 10:11

14

No. By definition Integer.MAX_VAlUE = 2^31 - 1

Integer.MAX_VALUE

answered Oct 21 '11 at 10:11

John B

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It goes further than that: the *compilation* platform makes **no difference at all**: the output will be the same. In an ideal world even the *runtime* platform would make no difference, but there might be minor differences here. – Joachim Sauer Oct 21 '11 at 13:07

score 5 · Answer 2 · answered Oct 21 '11 at 10:10

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No. The 32-bit JDK makes 32-bit addresses for the instances, and the 64-bit JDK makes 64-bit addresses for the object instances. Thus, Integer.MAX_VALUE is the same, because it's just an value, not an object address. :)

answered Oct 21 '11 at 10:10

Konstantin Yovkov

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Note that a 64bit JVM *can* use 32 bit references. See [CompressedOops](http://wikis.sun.com/display/HotSpotInternals/CompressedOops) for details. – Joachim Sauer Oct 21 '11 at 10:25

score 1 · Answer 3 · answered Oct 21 '11 at 10:11

1

This constant has the same value regardless of whether the JVM the code is running on is 32-bit or 64-bit. The documentation for Integer.MAX_VALUE describes this value as:

A constant holding the maximum value an int can have, 2³¹-1.

answered Oct 21 '11 at 10:11

Luke Woodward

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score 0 · Answer 4 · edited Aug 11 '14 at 04:48

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what all 32 bit and 64 bit resembles is the number of memory locations they can refer.. in case of 32 bit possible number of address will be 2^32 and in case of 64 bit it is 2^64.

The jvm version has nothing to do with Integer.MAX_VALUE , it will remain same.

edited Aug 11 '14 at 04:48

Andrew Barber

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answered Jul 22 '13 at 20:47

saurav

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score 0 · Answer 5 · edited May 23 '17 at 10:34

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You probably want to avoid comparing Integers using = sign due to:

Comparing Integers (provided aNumber is an object of class java.lang.Integer)

and no, there is no difference.

edited May 23 '17 at 10:34

Community

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answered Oct 21 '11 at 10:11

Wojciech Owczarczyk

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thank you for your extra information. just wondering in what situation do we need to reference check on (Integer == Integer)? Shouldn't we all always just need the value check? So why doesn't someone overload the operator '==' on Integer? – GaryX Oct 24 '11 at 02:40

Is there difference for Integer.MAX_VALUE between 32bit JVM and 64bit JVM?

5 Answers5