Only if isset() and value equality

Question

Just a simple php question, i have this:

if(isset($_GET['i'])) { if($_GET['i']=='dash') {

It is possible to use one IF? Thanks!

score 5 · Accepted Answer · answered Oct 22 '11 at 16:00

5

if (isset($_GET['i']) && $_GET['i'] == 'dash') {

This will test that both conditions return true in the test.

answered Oct 22 '11 at 16:00

Jared Farrish

Just to clarify, `&&` means `and`, you could use `||` for `or` if you wanted either condition to match. – Levi Morrison Oct 22 '11 at 16:02
What you might be asking is whether the `if($_GET['i']=='dash')` will throw an error if `$_GET['i']` is not set; it won't. PHP uses what's called "lazy evaluation," so if `$_GET['i']` is not set, PHP knows the entire if statement will fail so it will not evaluate `$_GET['i'] == 'dash'`. – toon81 Oct 22 '11 at 16:04
By the way if the first condition returns `false`, the second one will never be tested! So you simply can access `$_GET['i']` after you tested the existence in the IF. – ComFreek Oct 22 '11 at 16:05

score 2 · Answer 2 · answered Oct 22 '11 at 16:05

I do it this way:

function initGet($var, $default=''){
    if(!isset($_GET[$var])) return $default;
    return $_GET[$var];
}

So you can check it easy:

if(initGet('i')=='dash'){

And you could add a default value if needed:

if(initGet('i', 'dash')=='dash'){
     // would be true if $_GET['i'] is not set

score 1 · Answer 3 · answered Oct 22 '11 at 16:06

1

You can alternatively use array_intersect_assoc to check both conditions at once:

if (array_intersect_assoc($_GET, array("i" => "dash"))) {

answered Oct 22 '11 at 16:06

mario

3 Answers3