How do I get the external IP of my server using PHP?

Question

I often hear people say to use "$_SERVER['SERVER_ADDR']", but that returns the LAN IP of my server (e.g. 192.168.1.100). I want the external IP.

Answer 1

There is NO way to get your underlying IP Address that has been designated by your ISP via conventional PHP if you are using a router. A way to get the external IP is to find a service that will obtain it for you and echo the address back to you. I found a handy service which does just that. http://ipecho.net/

You can use:

$realIP = file_get_contents("http://ipecho.net/plain");

Answer 2

Just query a host that returns your IP address:

$externalContent = file_get_contents('http://checkip.dyndns.com/');
preg_match('/Current IP Address: \[?([:.0-9a-fA-F]+)\]?/', $externalContent, $m);
$externalIp = $m[1];

or, set up a service that simply echoes just the IP, and use it like this:

$externalIp = file_get_contents('http://yourdomain.example/ip/');

Set up the service yourself by simply echoing the remote IP address, or pay someone to host it. Do not use somebody else's server without permission. Previously, this answer linked to a service of mine that's now being hit multiple times a second.

Note that in an IP network with one or more NATs, you may have multiple external IP addresses. This will give you just one of them.

Also, this solution of course depends on the remote host being available. However, since there is no widely implemented standard (no ISP and only some home routers implement UPnP), there is no other way to get your external IP address. Even if you could talk to your local NAT, you couldn't be sure that there isn't another NAT behind it.

Answer 3

I'm going to add a solution because the others weren't quite right for me because they:

• need to be run on a server with a domain name e.g. gethostbyname() (if you think about it, you don't actually have the problem if you know this a priori)
• can't be used on the CLI (rely on something in $_SERVER to be set by a web server)
• assume a specific format of ifconfig output, which can include multiple non-public interfaces
• depend on parsing someone's website (who may disappear, change the URL, change the format, start lying to you, etc, all without notice)

This is what I would suggest:

$sock = socket_create(AF_INET, SOCK_DGRAM, SOL_UDP);
$res = socket_connect($sock, '8.8.8.8', 53);
// You might want error checking code here based on the value of $res
socket_getsockname($sock, $addr);
socket_shutdown($sock);
socket_close($sock);

echo $addr; // Ta-da! The IP address you're connecting from

The IP address there is a Google public DNS server. I trust they'll be around and running it for a while. It shouldn't really matter what address you use there as long as its a public IP address that belongs to someone who doesn't mind random connection attempts too much (yourself maybe?).

This is based on an answer I came across when I had a similar problem in Python.

---

P.S.: I'm not sure how well the above would work if there is sorcery going on between your machine and the internet.

Answer 4

You could parse it from a service like ip6.me:

<?php

// Pull contents from ip6.me
$file = file_get_contents('http://ip6.me/');

// Trim IP based on HTML formatting
$pos = strpos( $file, '+3' ) + 3;
$ip = substr( $file, $pos, strlen( $file ) );

// Trim IP based on HTML formatting
$pos = strpos( $ip, '</' );
$ip = substr( $ip, 0, $pos );

// Output the IP address of your box
echo "My IP address is $ip";

// Debug only -- all lines following can be removed
echo "\r\n<br/>\r\n<br/>Full results from ip6.me:\r\n<br/>";
echo $file;

Answer 5

You could try this:

$ip = gethostbyname('www.example.com');
echo $ip;

to get the IP address associated with your domain name.

Answer 6

I know this question is old and long answered, but I was googling for the same thing and want to add my own "hack". For this to work your webrequest has to come from an external IP address or you have to alter $own_url to a url that does an external request to itself.

The point is, if you let the script do a request to itself than you get it's external IP address.

<?php
if (isset($_GET['ip'])) {
    die($_SERVER['REMOTE_ADDR']);
}
$own_url = (isset($_SERVER['HTTPS']) ? 'https' : 'http') . '://'.$_SERVER['HTTP_HOST'].$_SERVER['SCRIPT_NAME'];
$ExternalIP = file_get_contents($own_url.'?ip=1');
echo $ExternalIP;
?>

Answer 7

I think there is much code for this things in others answers, but my answer is short, but you need to execute a command in shell to get the ip...

but it is short and fast, I think that...

php execute bash > bash run > bash get ip > php get ip

echo shell_exec( "dig +short myip.opendns.com @resolver1.opendns.com");

Sorry my for my english, I hope it help all you...

Reference: How can I get my external IP address in a shell script?

Answer 8

This is an old thread, but for what it's worth, I'm adding a simple function that I use. It uses outside services (which is inevitable it seems), but it provides a backup service as well, and local caching to avoid repetitive HTTP calls.

/*
USAGE
$ip = this_servers_public_ip(); // Get public IP, and store it locally for subsequent calls.
$ip = this_servers_public_ip(true); // Force remote query and refresh local cache if exists.
*/
function this_servers_public_ip($purge=false) {
    $local = sys_get_temp_dir().'/this.servers.public.ip';
    if ( $purge===true && realpath($local) ) {
        unlink($local);
    }
    if ( realpath($local) ) {
        return file_get_contents($local);
    }
    // Primary IP checker query.
    $ip = trim( file_get_contents('https://checkip.amazonaws.com') );
    if ( (filter_var($ip, FILTER_VALIDATE_IP) !== false) ) {
        file_put_contents($local,$ip);
        return $ip;
    }
    // Secondary IP checker query.
    $ip_json = trim( file_get_contents('https://ipinfo.io/json') );
    $ip_arr = json_decode($ip_json,true);
    $ip=$ip_arr['ip'];
    if ( (filter_var($ip, FILTER_VALIDATE_IP) !== false) ) {
        file_put_contents($local,$ip);
        return $ip;
    }
    return false; // Something went terribly wrong.
}

Answer 9

If your server have a domain name you can ping it or you can use:

$sMyServerIP = gethostbyname('yourdomain.com');
echo $sMyServerIP;

It will return your outer IP address.

Answer 10

Assuming your PHP is running on a Linux server you can call ifconfig using PHP's exec function. This will give public IP without need to contact some external website/service. E.g.:

$command = "ifconfig";  /// see notes below
$interface = "eth0";    // 
exec($command, $output);
$output = implode("\n",$output);
if ( preg_match('/'.preg_quote($interface).'(.+?)[\r\n]{2,}/s', $output, $ifaddrsMatch)
        && preg_match_all('/inet(6)? addr\s*\:\s*([a-z0-9\.\:\/]+)/is', $ifaddrsMatch[1], $ipMatches, PREG_SET_ORDER) )
{
    foreach ( $ipMatches as $ipMatch ) 
        echo 'public IPv'.($ipMatch[1]==6?'6':'4').': '.$ipMatch[2].'<br>';
}

Note that sometimes as $command you have to specify full path of ifconfig. You can find this by executing

whereis ifconfig

from shell prompt. Furthermore $interface should be set to the name of your server's main network interface that has the link to the WAN.

On Windows you can do something similar of course, using ipconfig instead of ifconfig (and corresponding adjusted regex).

Answer 11

Also you could get IP via DNS A record based on hostname or server name:

$dnsARecord = dns_get_record($_SERVER['HTTP_HOST'],DNS_A);
if ( $dnsARecord ) echo 'IPv4: '.$dnsARecord[0]['ip'];
$dnsARecord = dns_get_record($_SERVER['HTTP_HOST'],DNS_AAAA);
if ( $dnsARecord ) echo 'IPv6: '.$dnsARecord[0]['ip'];

You could also use SERVER_NAME instead of HTTP_HOST if one of the two does not give what you want.

However, this is assuming that your server is configured correctly in correspondence with DNS. This may not always be the case. See my other answer using ifconfig that is perhaps better.

Answer 12

Have you tried:

gethostbyname(php_uname('n'));

?