As we know that 4294967295 is the largest number in unsigned int
if I multiply this number by itself then how to display it? I have tried:
long unsigned int NUMBER = 4294967295 * 4294967295;
but still getting 1 as answer.
As we know that 4294967295 is the largest number in unsigned int
if I multiply this number by itself then how to display it? I have tried:
long unsigned int NUMBER = 4294967295 * 4294967295;
but still getting 1 as answer.
You are getting an overflow. Consider the muplication in hexadecimal:
0xffffffff * 0xffffffff == 0xfffffffe00000001
^^^^^^^^
only the last 32 bits are returned
The solution is to use a larger type such as long long unsigned
:
long long unsigned int NUMBER = 4294967295ULL * 4294967295ULL;
The suffix ULL
means unsigned long long
.
See it working online: ideone
The multiplication overflows.
#include <stdio.h>
int main()
{
unsigned int a = 4294967295;
unsigned int b = 4294967295;
// force to perform multiplication based on larger type than unsigned int
unsigned long long NUMBER = (unsigned long long)a * b;
printf("%llu\n", NUMBER);
}
You state in your question that you know max int is equal to 4294967295. That means that you can't store a number larger than that if you are using unsigned int.
C longs store up to 18,446,744,073,709,551,615 when unsigned on a 64 bit unix system [source] so you need only suffix your numbers with UL : 4294967295UL
If you aren't using a 64-bit unix system then you should use long long unsigned int
and suffix with LL
Yes, it's an overflow. If you are using c, there isn't any easy way to do such big number multiply as i knew. Maybe you need write one by yourself. In fact some language support such features originally.