Is it possible to replace previous command by '^' multiple times?

Question

In terminal, I can replace previous command by using '^' like:

$ ls -a 

$ ^a^l

$ ls -l

But, how can I replace multiple times? I mean:

$ ls a.jpg b.jpg c.jpg

$ /* something */

$ ls a.png b.png c.png

+1 for showing the `^a^b` syntax which is cool and new to me:) — Daniel Böhmer, Nov 02 '11 at 09:18
http://stackoverflow.com/questions/2149482/caret-search-and-replace-in-bash-shell — Frost, Nov 02 '11 at 09:21
You cannot use `^a^l` as a replacement "in terminal". It is valid syntax in `bash`, `csh`, and many other shells, but it is invalid in `dash`, `ksh`, and many other shells. The shell is not the terminal. — William Pursell, Nov 14 '12 at 16:13
Does this answer your question? [^word^replacement^ on all matches in Bash?](https://stackoverflow.com/questions/649070/wordreplacement-on-all-matches-in-bash) — Benjamin W., Sep 30 '21 at 09:23

score 3 · Answer 1 · answered Nov 02 '11 at 09:24

3

What you want is global replacements

!!:gs/jpg/png

answered Nov 02 '11 at 09:24

carrutherji

score 3 · Accepted Answer · answered Nov 02 '11 at 09:24

3

!:gs/jpg/png

answered Nov 02 '11 at 09:24

Ariel

infact, i found out ^foo^bar^ can do the same :) – Ya Zhuang Nov 15 '11 at 04:19
@bitsMix That only replaces one of them. – Ariel Nov 15 '11 at 05:00

2 Answers2