break integer into elements in an array

Question

I need to break an integer where each digit in this integer is to be an element in an array like this:

$x = 123;
var_dump($x_array);

Will out put something like this:

Array
(
    [0] => 1
    [1] => 2
    [2] => 3
)

Thanks.

Nicolas · Answer 1 · 2011-11-02T09:53:08.967

3

print_r(str_split($x));

Array ( [0] => 1 [1] => 2 [2] => 3 )

Don't forget the "php" tag next time!

edited Nov 02 '11 at 09:53

answered Nov 02 '11 at 09:43

Nicolas

Thanks to Graphox I got this solution: $x= 1234; $array = array(); $x = str_split($x); foreach($x as $number){ $number = intval($number); array_push($array,$number); } var_dump($x); var_dump($array); but after some work and the help of Ayyash I got this: $x = 1234; $y = 1; $array = array(); while($y){ $remainder = $x % 10 ; array_push($array, $remainder); $x = $x - $remainder; $x = $x /10; if($x == 0){ $y = 0; } } – saadlulu Nov 02 '11 at 10:19

score 1 · Accepted Answer · answered Nov 02 '11 at 10:00

(1) Array of digits as strings:

$x_array = str_split($x);
var_dump($x_array);

    0 => string '1' (length=1)
    1 => string '2' (length=1)
    2 => string '3' (length=1)

(2) Array of digits as integers:

$x_array = array_map('intval', str_split($x));
var_dump($x_array);

    0 => int 1
    1 => int 2
    2 => int 3

2 Answers2