Regex - how to extract text from between quotes and exclude quotes

Question

I need help with regex. I need to create a rule that would preserve everything between quotes and exclude quotes. For example: I want this...

STRING_ID#0="Stringtext";

...turned into just...

Stringtext

Thanks!

More info needed: Can there be more than one quoted string in your input? Can there be escaped quotes? Which regex engine are you using? — Tim Pietzcker, Nov 03 '11 at 16:16

score 4 · Answer 1 · answered Sep 05 '13 at 23:39

4

The way to do this is with capturing groups. However, different languages handle capturing groups a little differently. Here's an example in Javascript:

var str = 'STRING_ID#0="Stringtext"';
var myRegexp = /"([^"]*)"/g;
var arr = [];

//Iterate through results of regex search
do {
    var match = myRegexp.exec(str);
    if (match != null)
    {
        //Each call to exec returns the next match as an array where index 1 
        //is the captured group if it exists and index 0 is the text matched
        arr.push(match[1] ? match[1] : match[0]);
    }
} while (match != null);

document.write(arr.toString());

The output is

Stringtext

answered Sep 05 '13 at 23:39

dallin

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You can do this shorter: let result = []; let regex = /myRegex/g; let match = regex.exec(data); while(match) { result.push(match[1]); match = regex.exec(data); } – Kiechlus Apr 27 '16 at 12:43
Best answer because it does not produce errors in Safari either, since this regex does not use lookahead or lookbehind. – SlickRemix Jan 31 '22 at 20:39

score 1 · Answer 2 · answered May 03 '23 at 13:58

Try this

function extractAllText(str) {
       const re = /"(.*?)"/g;
        const result = [];
        let current;
        while ((current = re.exec(str))) {
            result.push(current.pop());
        }
        return result.length > 0 ? result : [str];
    }

const str =`STRING_ID#0="Stringtext"`
console.log('extractAllText',extractAllText(str));


document.body.innerHTML = 'extractAllText = '+extractAllText(str);

score 0 · Answer 3 · edited Feb 08 '17 at 14:46

0

"(.+)"$

Regular expression visualization

Edit live on Debuggex

This was asked in 2011.....

edited Feb 08 '17 at 14:46

Community

1
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answered Sep 05 '13 at 23:47

progrenhard

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score 0 · Answer 4 · edited Nov 03 '11 at 17:03

0

"([^"\\]*(?:\\.[^"\\]*)*)"

I recommend reading about REGEXes here

edited Nov 03 '11 at 17:03

a'r

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answered Nov 03 '11 at 16:18

Joao Figueiredo

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That doesn't remove the quotes from around the string. – Tim Pietzcker Nov 03 '11 at 16:28
Ouch, don't know how I forgot about it. But Tim Pietzcker is right, user should specify the REGEX engine – Joao Figueiredo Nov 03 '11 at 17:03

Regex - how to extract text from between quotes and exclude quotes

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