Defining "templated class" functions outside of a class

Question

I have this class

template <class T> class dynamic_array
  {

and this function:

void dynamic_array::randorder()
  {
  srand(time(NULL));
  int *ap;
  for(ap=array;k!=array+size;++k){*k=rand();} 
  }

The compiler is complaining about my function - "not having template parameters". How do I add this in?

score 8 · Accepted Answer · edited Nov 04 '11 at 19:34

8

template <class T>
void dynamic_array<T>::randorder()
{
  srand(time(NULL));
  for(int *ap = array; k != array + size; ++k)
  {
    *k = rand();
  }
}

edited Nov 04 '11 at 19:34

Stuart Golodetz

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answered Nov 04 '11 at 19:32

Yakov Galka

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Not intuitive...b.c. I do not use the template parameter in the function definition. – Nov 04 '11 at 19:33
2

@stack.user.1: you use. It's hidden in the type of array. – Yakov Galka Nov 04 '11 at 19:34

Dima · Answer 2 · 2011-11-04T19:38:24.207

It should be

template <class T>
void dynamic_array<T>::randorder()
  {
...
  }

Also, keep in mind that you have to put the definition into a header file if you need to use it in different .cpp files.

I suppose array must be a data member of type T, so the following doesn't apply here. But in general if you see that some member functions of a class template do not depend on the template parameters, it makes sense to factor them out into a non-template base class. It reduces the size of the executable and makes your life easier.

Defining "templated class" functions outside of a class

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