Jquery gives a Syntax error, unrecognized expression on calling a url including "("

Question

i am facing an error in Jquery Load function. I am using jquery to find a string in MySQL database table. here is a sample of my code.

nUrl='count.php?coun='+(code);
$('#memory2').load(nUrl);

here, i am using "code" as input. when i use "(" in code like:

code = "DQ118 (dq10)";

browser gives me an error like:

Uncaught Syntax error, unrecognized expression:  (

have you tried using the ascii codes for the brackets ( = ( and ) = ) — Richard Banks, Nov 07 '11 at 12:10

score 1 · Answer 1 · answered Nov 07 '11 at 12:15

1

First of all you must declare the variables ( var code = 'blah'; )

also, "escape" the string:

var code = escape("DQ118 (dq10)");
var nUrl = 'count.php?coun='+code;

answered Nov 07 '11 at 12:15

John

but i will use your code because it is short and understandable answer. – Shahrukh Nov 07 '11 at 12:32
@extremerose71: but also wrong. `code` has to be escaped, otherwise you may get strange responses – genesis Nov 07 '11 at 13:54

Nicola Peluchetti · Answer 2 · 2011-11-07T12:13:52.190

0

I've tried it and i don't get that error. In any case you should use encodeURIComponent i think on the code variable

code = encodeURIComponent("DQ118 (dq10)");
nUrl='count.php?coun='+code;
$('#example').load(nUrl);

edited Nov 07 '11 at 12:13

answered Nov 07 '11 at 12:08

Nicola Peluchetti

score 0 · Accepted Answer · answered Nov 07 '11 at 12:09

0

It works pretty fine, look here. Just maybe try to encode your URI, by using encodeURIComponent

code = "DQ118 (dq10)";
nUrl='count.php?coun='+encodeURIComponent(code);

and use var before you declare your variable. For example

var code = "DQ118 (dq10)";
var nUrl='count.php?coun='+encodeURIComponent(code);

so you avoid declaring your variable globally

answered Nov 07 '11 at 12:09

genesis

@extremerose71: Failed to load resource: the server responded with a status of 404 (Not Found) – genesis Nov 07 '11 at 12:14
@extremerose71: btw you have virus on very top of your page... be aware of that (iframe) – genesis Nov 07 '11 at 12:15
thanks for telling me about iframe. i know that. but problem is jquery did not send the string to the server. and gives the error for "(". – Shahrukh Nov 07 '11 at 12:22
Thanks @genesis for 1st Best and Thanks John for 2nd Best answer. – Shahrukh Nov 07 '11 at 12:30

score 0 · Answer 4 · edited May 23 '17 at 12:21

0

follow this previous question on this site Escaping HTML strings with jQuery

it is much clear to understand and help to solve further problems like this..

it works somewhat like this:

html.replace(/&/g, "&amp;").replace(/</g, "&lt;").replace(/>/g, "&gt;");

edited May 23 '17 at 12:21

Community

answered Nov 07 '11 at 12:26

Niranjan Singh

Thanks @Niranjan Kala but i have found a good and short solution form John. – Shahrukh Nov 07 '11 at 12:34

4 Answers4