How can I generate a url to a particular item in the Django Admin Site from a view?

Question

I would like to make a link that would take the user to a particular item in the admin site (assuming they have the correct permissions).

Can this be done with reverse?

see http://stackoverflow.com/questions/694477/getting-django-admin-url-for-an-object/2930241#2930241 — second, Nov 08 '11 at 22:07
@second - that question is from the good old Django 1.0 days, so there's quite a lot of noise. I've tried to summarise the information below. — Alasdair, Nov 08 '11 at 22:19

Alasdair · Accepted Answer · 2021-11-10T21:59:13.733

22

You can get the url in the view, using reverse,

object_change_url = reverse('admin:myapp_mymodel_change', args=(obj.id,))

Or in the template, using the url tag

{% url 'admin:myapp_mymodel_change' obj.id %}

or

{% load admin_urls %}
{% url opts|admin_urlname:'change' obj.id %}">

Note the above url tag syntax is for Django >= 1.5.

For more information, see the Django docs on reversing admin urls.

edited Nov 10 '21 at 21:59

answered Nov 08 '11 at 22:17

Alasdair

Is `obj` supposed to stand in here for your model? I got it to work by replacing `obj` with my model name, is that how it's supposed to work? – David Rhoden Nov 10 '21 at 16:15
1

@DavidRhoden it’s a long time since I wrote the answer. Looking at the docs, I think it should be `opts` not `obj` – Alasdair Nov 10 '21 at 21:57
1

Thanks. Old answer, but it got me where I needed to go. – David Rhoden Nov 10 '21 at 22:46

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