how to represent following string using regular expression?

Question

I want to represent following string using regular expression.

This is the sentence:

pro displ = "monitor" id="1"

I tried this:

pro displ=(("[^"]*")monitor(("[^"]*") id =(("[^"]*")1(("[^"]*")

but it is not working.as i was new to regular expression please help me to solve this issue

What is the string you want to anlyze, what is the value you want to get and what is your regex? — Fischermaen, Nov 10 '11 at 15:06
And what value to want to get out of the string? Or do you just want to check the whole string? — Fischermaen, Nov 10 '11 at 15:11
@Nithin: You're trying to [match XML with REs](http://stackoverflow.com/questions/1732348/regex-match-open-tags-except-xhtml-self-contained-tags/1732454#1732454)? — Donal Fellows, Nov 10 '11 at 15:43

moongoal · Answer 1 · 2011-11-10T15:57:15.223

0

<prop.*disp=\"(.*)\".*id=\"(.*)\".*>

You can use this one, and then match the parentheses to change what you want.

Instead this one with the 'sed' utility:

<prop.*disp=\"\(.*\)\".*id=\"\(.*\)\".*>

edited Nov 10 '11 at 15:57

answered Nov 10 '11 at 15:26

moongoal

actually i want to check xml node starting .so i want regular expression equivalent to this to so that i can replace this with another one such as – Nithin Nov 10 '11 at 15:34
Try with this new one, I succesfully used it with JS. – moongoal Nov 10 '11 at 15:58
Regex="<Prop Display =\"\ Monitor\" id=\"\1\" >(.*?)</Prop>".i tried like this but it is not working .the problem is due t the double quotes.how to represent double quotes using regular expression – Nithin Nov 11 '11 at 05:16
Where are you using this expression? The syntax has little differences depending on the program/API you use.. Usually double quotes are represented by escaping them, such as: \" – moongoal Nov 11 '11 at 09:38

score -1 · Answer 2 · edited Nov 11 '11 at 18:08

-1

I think this should work to match the string:

pro\sdispl=["]monitor["]\sid=["]1["]

edited Nov 11 '11 at 18:08

Samuel Liew

answered Nov 10 '11 at 15:40

rl22

i tried like this (("[^"]*")for doubles quotes but it is showing some error in msbuild.i think that error is due to the [ square bracket. – Nithin Nov 10 '11 at 15:45

2 Answers2