In C#, is there a way to set a variable from a switch expression? For example:
var a = switch(b)
{
case c:
d;
case e:
f;
default:
g;
};
Is it possible in any other language?
In C#, is there a way to set a variable from a switch expression? For example:
var a = switch(b)
{
case c:
d;
case e:
f;
default:
g;
};
Is it possible in any other language?
From C# 8 onwards:
Yes, switch expressions were introduced in C# 8. In terms of syntax, the example would be:
var a = b switch
{
c => d,
e => f,
_ => g
};
... where c
and e
would have to be valid patterns to match against b
. _
represents the default case.
Before C# 8:
No, switch
is a statement rather than an expression which can be evaluated.
Of course, you can extract it into another method:
int x = DoSwitch(y);
...
private int DoSwitch(int y)
{
switch (y)
{
case 0: return 10;
case 1: return 20;
default: return 5;
}
}
Alternatively, you could use a Dictionary
if it's just a case of simple, constant mappings. If you can give us more information about what you're trying to achieve, we can probably help you work out the most idiomatic way of getting there.
No, you can't use a switch statement as an expression. Another way to write it is nested conditional operators:
var a = b == c ? d:
b == e ? f:
g;
I just wanted to add that Jon Skeet's answer here will not compile and result in an error, since the C#8 switch assignment needs to be closed off with a semicolon.
var a = b switch
{
c => d,
e => f,
_ => g
}; //<-- here
/I am lacking the reputation to comment this under his answer, but since his is the top answer, it should be noted./
I edited the answer in question now
This is not possible in C#.
The closest would be to either move this into a method, or do the assignment in each case individual, ie:
int a;
switch(b)
{
case c:
a = d; break;
case e:
a = f; break;
default:
a = g; break;
};
Is it possible in any other language?
Yes. For example, most functional languages support something similar. For example, F#'s pattern matching provides a (much more powerful) version of this.
If you weren't especially concerned about efficiency, it would be pretty easy to cook up a little class using generics that allowed you to use a "fluent" chain of method calls such as this:
var a=Switch(b).Case(c).Then(d).Case(e).Then(f).Default(g);
or, if you prefer, the more compact
var a=Switch(b).Case(c, d).Case(e, f).Default(g);
If this interests you, I'd be happy to cook up an example
switch
in C# is a statement that doesn't have a "return" value. If you're interested in having a "switch" expression, you can find the little fluent class that I wrote here in order to have code like this:
a = Switch.On(b)
.Case(c).Then(d)
.Case(e).Then(f)
.Default(g);
You could go one step further and generalize this even more with function parameters to the Then
methods.
You can do it since c# 8.0, it is called "Switch expressions":
const int c = 1;
int d = 2;
const int e = 3;
int f = 4;
int g = 5;
int b = 3;
var a = b switch
{
c => d,
e => f,
_ => g,
};
Console.WriteLine(a);
a
will contain value 4
c
and e
should be constants as per switch syntax, _
corresponds to the default switch branch
I wanted the same thing because I use Ruby quite a lot, and that allows you to do that kind of thing. So I created a nuget package called FluentSwitch.
No.
A switch
statement provides branching control. It is not a function that evaluates to something that could be assigned to a variable.