5

I am making application in c#.Here i want to convert a byte array containing hex values to decimal values.Suppose i have one byte array as

array[0]=0X4E;
array[1]=0X5E;
array[2]=0X75;
array[3]=0X49;

Here i want to convert that hex array to decimal number like i want to concatenate first all bytes values as 4E5E7549 and after that conversion of that number to decimal.I dont want to convert each separate hex number to decimal.The decimal equivalent of that hex number is 1314813257.So please help me.Thanks in advance.

Bali C
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user1051703
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    BitConverter.ToInt32() was made to do this. Although you do have to observer little-endian byte order. Array.Reverse() if you have to. – Hans Passant Nov 17 '11 at 12:11

5 Answers5

10

The BitConverter.ToInt32 method is a good way to do this

if (BitConverter.IsLittleEndian)
    Array.Reverse(array); //need the bytes in the reverse order
int value = BitConverter.ToInt32(array, 0);
Ray
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  • reversing gives absolutely required result but i couldn't understand why we have to do reversing, i might be missing some point but in my view last byte in array should represent the lower byte of the number, right? – Mubashar Oct 23 '13 at 01:41
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    got the answer here http://betterexplained.com/articles/understanding-big-and-little-endian-byte-order/ – Mubashar Oct 23 '13 at 01:52
1

hex and decimal are just different ways to represent the same data you want something like

int myInt = array[0] | (array[1] << 8) | (array[2] << 16) | (array[3] <<24)
Yaur
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1

Here's a method to convert a string containing a hexadecimal number to a decimal integer:

private int HexToDec(string hexValue)
{
    char[] values = hexValue.ToUpperInvariant().ToCharArray();
    Array.Reverse(values);
    int result = 0;
    string reference = "0123456789ABCDEF";

    for (int i = 0; i < values.Length; i++)
        result += (int)(reference.IndexOf(values[i]) * Math.Pow(16d, (double)i));

    return result;
}

You can then string the pieces together and pass them to this function to get the decimal values. If you're using very large values, you may want to change from int to ulong.

John Willemse
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0

Instead of checking IsLittleEndian by yourself, you can use IPAddress.NetworkToHostOrder(value).

int value = BitConverter.ToInt32(array, 0);

value = IPAddress.NetworkToHostOrder(value);

See more:

https://learn.microsoft.com/de-de/dotnet/api/system.net.ipaddress.networktohostorder?redirectedfrom=MSDN&view=netframework-4.7.2#System_Net_IPAddress_NetworkToHostOrder_System_Int32_

shtse8
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0

Mind the byte order.

int num = 
    array[0] << 8 * 3 | 
    array[1] << 8 * 2 | 
    array[2] << 8 * 1 | 
    array[3] << 8 * 0;
Michał Powaga
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