Can I alias a key in an object literal?

Question

Possible Duplicate:
Self-references in object literal declarations

I have an object literal which is used as a configuration element and is looked up for keys.

customRendering:{
                  key1: func(){....},
                  key2: func(){....}
}

I have a situation where key2 and key3 can use the same function. Is there a way to assign the same function to both key2 and key3 without having to declare the function outside the object literal and without having to declare an extra key?

I was hoping I could do something like:

key2: key3: func(){....}

Answer 1

A safe way:

I don't know what I was thinking earlier. If you're fine with using a more verbose "literal" you can instantiate a custom function:

o = new function () {
  this.foo = function () { console.log('works'); };
  this.bar = this.foo;
};

This is a dirty nasty hack:

you could use a temporary variable to store the reference to the function while setting the object. Be careful to use a closure and to call var before using it so that you don't pollute the global namespace:

(function () {
  var o, baz;
  o = {
    foo: baz = function () {console.log('works')},
    bar: baz
  }
  //more code
}());

The reason I'm calling this a dirty nasty hack is that it makes the code less readable, it's harder to tell examining this code (especially if the object literal declaration was longer) where baz was set.

Better to just write the alias outside the object literal so that it's explicitly visible that it is an alias.

Note: the named function format doesn't work:

o = { //THIS WON'T WORK
  foo: function baz() {/* code */},
  bar: baz
}

---

There's no way within an object literal to define an alias using a shared reference.

You can use an aliasing function, but it wont be an identical reference:

o = {
  foo: function...
  bar: function () { return this.foo() } //even better if you use `apply` or `call`
}

The typical way to share a reference is after the object literal, which sounds like what you wanted to avoid:

o = {
  foo: function...
}
o.bar = o.foo;

Alternatively as you pointed out in your question (and for completeness) you could define the function outside of the object literal:

func = function () {/* code */};
o = {
  foo: func,
  bar: func
}

_{In response to @Peter about returning an object from a function}

Using a self-executing anonymous function is another way of instantiating an object inline, and would make this entire question moot:

o = (function () {
  var o = {
    foo: function () {/*code*/}
  }
  o.bar = o.foo;
  return o;
}());

Or like this:

var o = (function () {
  var shared = function() { console.log("shared") };
  return {
    foo: shared,
    bar: shared
  }
}());

Answer 2

without having to declare the function outside the object literal

I think this part makes it impossible. However, while I use JavaScript all the time, I am not a professional JS ninja, so perhaps I am wrong.

Code for how I would do this (although it seems you already know you can do this, I thought it might be best to say it anyway):

customRendering = {};
customRendering.key1 = func(){....};
customRendering.key2 = customRendering.key1;

Answer 3

Define the function aside from the object:

var func = function() { ... };
...
  customRendering: {
    key1: func,
    key2: func
  }

Answer 4

Sorry I understood your question incorrectly.

Here is a possible solution:

    var obj = {
      func1: function() {},
      func2: obj.func1
    }