converting a URL

Question

I have a method

String Address=search.getText().toString();

private String getAddressUrl() {
     String mapUrl="http://maps.googleapis.com/maps/api/geocode/json?";
     String add=Address; //Address is a String input by the user  
     String baseUrl1=mapUrl+"address="+add+"&sensor=true";
return baseUrl1;
}

If I input the string like "170 william street New York, NY" I am getting illegal character at query error because it contains spaces.

Is there any method to insert %20 for spaces in Address string

Check out http://stackoverflow.com/questions/573184/java-convert-string-to-valid-uri-object — skyuzo, Nov 20 '11 at 09:12
on a side note - Try using beginning lower case letters for local variable names and fields like `Address`, this will make it easier for other java programmers to read your code. — vidstige, Nov 20 '11 at 09:24

score 5 · Accepted Answer · answered Nov 20 '11 at 09:15

5

Look at Uri.encode(String).

String add=Uri.encode(Address);

answered Nov 20 '11 at 09:15

kabuko

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score 1 · Answer 2 · answered Nov 20 '11 at 09:18

1

You should use class UrlEncoder

answered Nov 20 '11 at 09:18

Eugen Martynov

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A little gotcha with URLEncoder: It will encode spaces as `+` instead of `%20`. – Muz Oct 09 '12 at 04:50

score 0 · Answer 3 · answered Nov 20 '11 at 09:22

0

Oops, thought this was .Net for some reason.

answered Nov 20 '11 at 09:22

Andy

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converting a URL

3 Answers3