Replacing an XML node with Anti-XML

Question

I am struggling to replace a XML element with another one using the library anti-xml. For instance, I have:

<root>
  <sub>
    <keep />
    <replace />
    <keeptoo />
  </sub>
</root>

and the fragment:

<inserted key="value">
  <foo>foo</foo>
  <bar>bar</bar>
</inserted>

I would like to produce:

<root>
  <sub>
    <keep />
    <inserted key="value">
      <foo>foo</foo>
      <bar>bar</bar>
    </inserted>      
    <keeptoo />
  </sub>
</root>

Note: The order of <sub> children must be conserved.

David · Accepted Answer · 2011-11-20T14:26:13.120

3

First we define the root document :

val root = 
<root>
  <sub>
    <keep />
    <replace />
    <keeptoo />
  </sub>
</root>.convert

val inserted =
  <inserted key="value">
    <foo>foo</foo>
    <bar>bar</bar>
 </inserted>.convert

then we get the element :

val replace = root \\ 'replace

and finally we get the xml with updated <replace/> node :

replace.updated(0, inserted).unselect

if we get multiple <replace/> nodes, we will be able to iterate over replace to update each node.

edited Nov 20 '11 at 14:26

answered Nov 20 '11 at 14:17

David

2,399
20
17

Thanks for your answer. Any idea how I can replace the `` element by a list of several nodes ? – paradigmatic Nov 21 '11 at 09:36
I'm not sure that it's possible but I'm not an antixml expert. Could you consider to have ``, `` ... and to replace them individually ? – David Nov 21 '11 at 11:14
No, because I don't know in advance how many nodes I should add. I use another approach now, but I will fill another question about it, if I meet the problem again. – paradigmatic Dec 07 '11 at 07:55

score 2 · Answer 2 · answered Mar 16 '12 at 14:34

2

You can replace selected elements with several nodes using flatMap, e.g. replace.flatMap(_ => someListOfNodes).unselect

(Sorry for making it a separate answer, it appears that I can't comment on existing ones.)

answered Mar 16 '12 at 14:34

ncreep

473
3
11

Replacing an XML node with Anti-XML

2 Answers2