Initialization of object with default constructor

Question

Possible Duplicate:
Most vexing parse: why doesn't A a(()); work?
Difference between creating object with () or without

There is such code:

class MojaKlasa{
public:
  MojaKlasa(){}
  MojaKlasa(int i){}
  void fun(){}
};

int main()
{
  MojaKlasa a;
  a.fun();

  MojaKlasa b(1);
  b.fun();

  MojaKlasa c(); //  initialize with default constructor
  //c.fun(); error: request for member ‘fun’ in ‘c’, which is of non-class type ‘MojaKlasa()’

  return 0;
}

Why is there error for object c?
What is the way to make it work?
What does really mean MojaKlasa c() - is it function declaraton?

It's not the most vexing parse, the most vexing parse is when you try to use a value initialized temporary as initializer in a direct-initialized declaration. — CB Bailey, Nov 20 '11 at 15:20

score 4 · Answer 1 · answered Nov 20 '11 at 15:15

MojaKlasa c();

This declares a function called c returning MojaKlasa, it's not an object declaration. If you want to declare a local object you need to omit the parentheses. It's just a language rule that the compiler has to interpret this form as a function declaration.

MojaKlasa c;

score 2 · Answer 2 · answered Nov 20 '11 at 15:17

2

MojaKlasa c();

defines a function returning a MojaKlasa object.

MojaKlasa c;

defines an object c of type MojaKlasa.

answered Nov 20 '11 at 15:17

Werner Henze

16,404
12
44
69

Initialization of object with default constructor

2 Answers2