IntentService doesn't start from BroadcastReceiver

Question

I am trying to start IntentService from BroadcastReceiver like ( in onReceive(Context context, Intent intent) function):

            Intent i = new Intent(context, RegService.class);
            i.putExtra("user_id", userId);
            i.putExtra("device_id", "bla");
            context.startService(i);

and RegService like

public class RegService extends IntentService {

    public RegService(String name) {
        super(name);
    }

    public RegService(){
        super("RegService");    
    }



    @Override
    protected void onHandleIntent(Intent intent) {
        // TODO Auto-generated method stub
        String c2dm_registration_id = intent
                .getStringExtra("c2dm_registration_id");
        String token = intent.getStringExtra("token");
        String userId = intent.getStringExtra("user_id");
        String device_type = "android";
        try {

            JSONObject object = RestClient.sendC2DMRegistrationId(
                    c2dm_registration_id, device_type,
                    token, userId);
        } catch (Exception e) {
            e.printStackTrace();
        }
    }

}

but I cannot enter in onHandle in RegService ( I passed through first code context.startService(i); but I cannot enter in onHandle, no message ). Did anybody have same experience and waht is a solution ? I have in manifest

<service
        android:enabled="true"
        android:name=".c2dm.RegService" />

I dont understand your question to well. "like ( in onReceive(Context context, Intent intent) function):" where is this "onReceive" method your referring too? Also the last paragraph, what does "i cannot enter in onHandle in RegService" mean? — owen gerig, Nov 23 '11 at 16:30
also posting your manifest.xml might help a little, since i believe your service should be defined in there as well. — owen gerig, Nov 23 '11 at 16:32
@owengerig inside BroadcastReceiver class inside method onReceive I am executing code with context.startService. I cannot enter means that program never reaches that point or function. But from code above you can see that you can expect to enter in that function. — Damir, Nov 23 '11 at 16:34
dont know a specific answer but i belive the name needs to match what the intent is calling. like this http://stackoverflow.com/questions/3439356/unable-to-start-service-intent — owen gerig, Nov 23 '11 at 16:44
I take it RegService is in the package: application_package.c2dm ? — FunkTheMonk, Nov 23 '11 at 16:48

score 3 · Answer 1 · answered Jul 21 '14 at 11:35

When my IntentService was declared with just its class name in the manifest,then I was not able to call it from the Broadcast Receiver.I then gave the full name like :

<service  android:name="com.abc.def.services.DummyService" />

This did the trick and I was able to invoke this IntentService from within the Broadcast Receiver.

score 1 · Answer 2 · answered Nov 23 '11 at 16:26

1

Have you declared the service in the manifest?

If so and it does not work try to set an action on the intent anyway, evenhough you won't use it.

answered Nov 23 '11 at 16:26

gwvatieri

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IntentService doesn't start from BroadcastReceiver

2 Answers2