Count total search objects count in template using django-haystack

Question

I am using django haystack with xapian as the backend search engine. I am using FacetedSearchView and FacetedSearchForm for faceting over the search. I have passed searchqueryset to the FacetSearchView in my urls.py file.

But the problem is I cannot access that searchqueryset in template. All I want to do is count the number of objects in searchqueryset found.

In shell I could achieve it using SearchQuerySet().filter(content="foo").count(), how can I do that similarly in the template? Please guide. I want the total number of objects matching the search.

score 33 · Accepted Answer · edited Jul 15 '15 at 13:56

33

Haystack uses the standard django pagination: https://docs.djangoproject.com/en/dev/topics/pagination/

Showing {{ page.object_list|length }} of {{ page.paginator.count }} Results on Page {{ page.number }} of {{ page.paginator.num_pages }}

edited Jul 15 '15 at 13:56

Below the Radar

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answered Nov 29 '11 at 15:26

Francis Yaconiello

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mynameistechno · Answer 2 · 2013-03-29T19:55:59.640

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If you want to show the result range instead of page number, e.g. "Results 21-40 of 1001", You can do

Results {{ page.start_index }} - {{ page.end_index }} of {{ page.paginator.count }}

edited Mar 29 '13 at 19:55

answered Mar 29 '13 at 15:59

mynameistechno

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score 0 · Answer 3 · edited Nov 28 '11 at 07:51

0

{{ page.object_list | length }}

edited Nov 28 '11 at 07:51

stema

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answered Nov 27 '11 at 21:57

soField

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this only tells you how many objects are on this page of results. It doesn't tell you how many results were returned in total (ex: Showing 20 of 53 - Showing {{ page.object_list | length }} of {{ HOW DO YOU GET THIS NUMBER OVER HERE}}) – Francis Yaconiello Nov 29 '11 at 15:17

Count total search objects count in template using django-haystack

3 Answers3

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