How can I create loop using int value in c++ (simple)

Question

I have an integer value, such as 5794. I want apply a several of calculations on each number without using array

Example

int encrypt;
cout << "Enter 4 digit numbers to encryption :> ";

cin >> encrypt;

for(int i=1;i<=encrypt;i++){
   cout << encrypt  << endl;
}

This code prints the whole number, but I want to print each digit without using array. If the number is 5794, I want to display:

I do not want it to be displayed like this:

Side note: [endl vs '\n'](http://stackoverflow.com/questions/213907/c-stdendl-vs-n) — Joe McGrath, Nov 28 '11 at 02:43

KV Prajapati · Answer 1 · 2011-11-28T03:06:41.750

4

Hint: Use modulus (%) and division (/) operator.

If given number has four digit then divide it by 1000,100,10,1:

std::cout << "\n" << encrypt/1000%10;
std::cout << "\n" << encrypt/100%10;

edited Nov 28 '11 at 03:06

answered Nov 28 '11 at 02:31

KV Prajapati

93,659
19
148
186

thanks, but I do not mean this, I want print number like 5487 each number individually not all the numbers together with some. This is the simplest thing I want – Lion King Nov 28 '11 at 03:35

score 1 · Answer 2 · answered Nov 28 '11 at 02:31

1

well, if you have the number 5794, you need to mathmatically extract the digits.

HINT: What happens if you divide the number by 1000?

answered Nov 28 '11 at 02:31

Keith Nicholas

43,549
15
93
156

@Maxpm: thanks, but please give me example code, I'm beginner – Lion King Nov 28 '11 at 03:03
@LionKing `std::cout << encrypt / 1000;` – Maxpm Nov 28 '11 at 03:10
@Maxpm: I do not mean this, I want print number like 5487 each number individually Not all the numbers together with some. This is the simplest thing I want – Lion King Nov 28 '11 at 03:35
@LionKing I know. You need to get single digits out of an arbitrary number. To do that, use `/` and `%`. – Maxpm Nov 28 '11 at 03:47
@Maxpm: thanks for continue help me, Ok but how can I print number like 5974 each single number in line, can you tell me example please . – Lion King Nov 28 '11 at 03:56
@LionKing: According to your example output, you want one digit per line followed by a blank line. – Thomas Matthews Nov 28 '11 at 04:39

score 0 · Answer 3 · answered Nov 28 '11 at 02:35

0

Scan number, then you can extract each digit using integer division and reminder (%) operators.

answered Nov 28 '11 at 02:35

Petr Abdulin

33,883
9
62
96

score 0 · Answer 4 · answered Nov 28 '11 at 03:14

0

is this you want?:

// get the number from stdin, std::cin >> v; 
visitNumber(int v)
{
    int v1 = v;
    size_t len = 0;

    while(v1){
        v1 /= 10;    
        ++ len;
    }

    for(int i=len; i>0; --i){
        std::cout << (v/pow(10,i)) << std:endl; // or some other op you favorate
    }
}

answered Nov 28 '11 at 03:14

Haiyuan Li

377
2
10

thanks, but I do not mean this, I want print number like 5487 each number individually Not all the numbers together with some. This is the simplest thing I want – Lion King Nov 28 '11 at 03:37

Thomas Matthews · Accepted Answer · 2011-11-28T06:17:44.427

-1

Since you have troubles putting other replier's suggestions into code:

int divisor = 1000;
std::cout << "enCRAPtion digits:\n";
for (unsigned int j = 0; j < 3; ++j)
{
    cout << (encrypt / divisor) << "\n\n";
    encrypt = encrypt % divisor;
    divisor = divisor / 10;
}

By the way, the word is "encryption" not "encraption".

edited Nov 28 '11 at 06:17

answered Nov 28 '11 at 04:37

Thomas Matthews

56,849
17
98
154

Thanks for your help, your code is the closest to the correct, But there is a problem , when print the number as this way, example if the number is (4567), Printed in this way 4 45 456 4567 and I want like this 4 5 6 7 . – Lion King Nov 28 '11 at 05:14

How can I create loop using int value in c++ (simple)

5 Answers5