Increase current date by 5 days

Question

$date = date('Y-m-d',current_time('timestamp', 0));

How do I change $date to $date + 5 days?

PHP version is 5.2.

This code doesn't work:

$date_cur = date('Y-m-d',current_time('timestamp', 0));
echo $date_cur . ' <br>';
$date_cur_plus = date($date_cur, strtotime('+5 days'));
echo $date_cur_plus;

Gives me:

2011-11-29 
2011-11-29

duplicate of all of those http://stackoverflow.com/search?q=add+days+php — Gordon, Nov 29 '11 at 09:11
possible duplicate of [Add number of days to a date](http://stackoverflow.com/questions/2332681/add-number-of-days-to-a-date) — edorian, Nov 29 '11 at 09:13

score 40 · Answer 1 · answered Nov 29 '11 at 08:51

40

$date = date('Y-m-d', strtotime('+5 days'));

answered Nov 29 '11 at 08:51

matino

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I mean date($date_cur, strtotime('+5 days')); gives the same result, as the $date_cur – Jasper Nov 29 '11 at 09:05
1

I suggest you check how does date function work - http://php.net/manual/en/function.date.php – matino Nov 29 '11 at 09:06

Yes Barry · Accepted Answer · 2011-11-29T09:15:50.217

19

You could use mktime() using the timestamp.

Something like:

$date = date('Y-m-d', mktime(0, 0, 0, date('m'), date('d') + 5, date('Y')));

Using strtotime() is faster, but my method still works and is flexible in the event that you need to make lots of modifications. Plus, strtotime() can't handle ambiguous dates.

Edit

If you have to add 5 days to an already existing date string in the format YYYY-MM-DD, then you could split it into an array and use those parts with mktime().

$parts = explode('-', $date);
$datePlusFive = date(
    'Y-m-d', 
    mktime(0, 0, 0, $parts[1], $parts[2] + 5, $parts[0])
    //              ^ Month    ^ Day + 5      ^ Year
);

edited Nov 29 '11 at 09:15

answered Nov 29 '11 at 08:50

Yes Barry

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How do I make new variable +5 days from $date_cur? – Jasper Nov 29 '11 at 09:01
Where are you getting method `current_time()` from? try using `time()`. – Yes Barry Nov 29 '11 at 09:02
`$date_cur_plus = date('Y-m-d', strtotime('+5 days'));` – Yes Barry Nov 29 '11 at 09:06
I have to increase the variable, because it is stored in database. – Jasper Nov 29 '11 at 09:12
Gotcha. Check my edit which has been modified per your question. – Yes Barry Nov 29 '11 at 09:30

score 5 · Answer 3 · answered Feb 16 '16 at 14:32

5

Object oriented Style:

<?php
    $date = new DateTime('now');
    $date->add(new DateInterval('P5D'));
    echo $date->format('Y-m-d') . "\n";
?>

Procedural Style:

<?php
    $date = date_create('2016-01-01');
    date_add($date, date_interval_create_from_date_string('5 days'));
    echo date_format($date, 'Y-m-d');
?>

answered Feb 16 '16 at 14:32

Turdaliev Nursultan

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@matino has the nicest procedural answer, but I like this OOP one very much. – Prikkeldraad Feb 16 '16 at 14:46

score 4 · Answer 4 · answered Feb 11 '19 at 01:52

4

For specific date:

$date = '2011-11-01';
$date_plus = date('Y-m-d', strtotime($date.'+5 days'));
echo $date.'<br>'.$date_plus;

It will be give :

2011-11-01
2011-11-06

answered Feb 11 '19 at 01:52

Irfan Hafid Nugroho

390
3
4

score 4 · Answer 5 · answered Nov 29 '11 at 08:50

4

Use strtotime:

$date = date('Y-m-d', strtotime('+5 days'));

answered Nov 29 '11 at 08:50

phihag

278,196
72
453
469

how to add 5 days in a given date @phihag – Amanjot Kaur Mar 07 '17 at 05:00

score 3 · Answer 6 · answered Nov 29 '11 at 08:51

3

$dateplus5 = date('Y-m-d', strtotime('+5 days'));

answered Nov 29 '11 at 08:51

Francis Avila

31,233
6
58
96

score 2 · Answer 7 · edited Jun 20 '20 at 09:12

strtotime() is very nice. It allows you to do the following:

$startDate = 'now'; // or choose a certain date you want/have
$startDate = '2013-02-14';
$intervals = array(
    '', 
    '+ 5 days', 
    '+ 31 days', 
    '+ 3 months', 
    '+ 2 years + 2 days'
); 
foreach($intervals as $interval) {
    $combinedDate = $startDate . ' ' . $interval;
    var_dump($combinedDate . ' => ' date('Y-m-d', strtotime($combinedDate)));
}

with a result:

now => 1360334498 = 2013-02-08

now + 5 days => 1360766498 = 2013-02-13

now + 31 days => 1363012898 = 2013-03-11

now + 3 months => 1368020498 = 2013-05-08

now + 2 years + 2 days => 1423579298 = 2015-02-10

or:

2013-02-14 => 1360792800 = 2013-02-14

2013-02-14 + 5 days => 1361224800 = 2013-02-19

2013-02-14 + 31 days => 1363471200 = 2013-03-17

2013-02-14 + 3 months => 1368478800 = 2013-05-14

2013-02-14 + 2 years + 2 days => 1424037600 = 2015-02-16

score 2 · Answer 8 · answered Nov 29 '11 at 08:51

2

You can use

strtotime(“+5 days”)

to get the current date plus 5 days or

$targetDate = date($date, strtotime(’+5 days’));

answered Nov 29 '11 at 08:51

Taz

1,235
9
16

score 0 · Answer 9 · edited Sep 04 '15 at 11:54

0

I used this:

$date = strtotime("+1 day", strtotime("2007-02-28"));
echo date("Y-m-d", $date);

It's working now.

edited Sep 04 '15 at 11:54

Rory McCrossan

331,213
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339

answered Sep 04 '15 at 11:36

bharati bane

1

score 0 · Answer 10 · answered Dec 26 '16 at 03:12

0

Did not supposed to be like this?

$date_cur = date('Y-m-d', current_time('timestamp', 0));
echo $date_cur . ' <br>';
$date_cur_plus = date('Y-m-d', strtotime('+5 days', current_time('timestamp', 0) ) );
echo $date_cur_plus;

answered Dec 26 '16 at 03:12

Lafif Astahdziq

3,788
29
38

score 0 · Answer 11 · answered Nov 10 '17 at 07:41

0

if the date is already exists, you can used this code :

$tartDate = date("m/d/Y", strtotime("+1 Day", strtotime($Date)));

answered Nov 10 '17 at 07:41

Muh faris

197
2
6

Increase current date by 5 days

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