How can I change the running directory of a program - by setting it in the exe shortcut?

Question

I have an exe process that is running with a shortcut.
In the "Start in" property of the shortcut I set it to the folder where all app resources are. The process still looks for files at the location of the exe and not the location written in the shortcut.

I can also see it in Process Explorer - the "current directory" is the location of the exe.
Is there a way to change it?

(If I wasn't clear enough - I want to put my app in a central network location and not in each user folder - but I want it to run - above each user folder by putting a shortcut in each user folder.)

BTW : Why don't I solve it with code writing? Because of third party jars I have in my exe (I am using exe4j to make an exe)

Answer 1

From exe4-j documentation.., it seems this can be configured in exe4j project.

Working directory
For some applications (especially GUI applications) you might want to change the working directory
to a specific directory relative to the executable, for example to read config files that are in a fixed
location. To do so, please select the Change working directory to: checkbox and enter a
directory relative to the executable in the adjacent text field. To change the current directory to the
same directory where the executable is located, please enter a single dot.

Answer 2

One alternative is to use a System Property. Just create a shortcut like this:

java -Dmyproperty="\\myserver\myfolder" -jar yourjar.jar

And get this property on your program:

System.getProperty("myproperty");

You can also set multiple System Properties.

Answer 3

I would start the java application via a cmd or bat file, then change to the work dir before you call javaw. If you don't do any thing special in your java application code all the paths in it will be relative to the place where you started java.

Jess

Answer 4

You can hack the classpath programatically which would allow you to specify a specific folder or series of folders to access the data.

import java.io.IOException;
import java.io.File;
import java.net.URLClassLoader;
import java.net.URL;
import java.lang.reflect.Method;

public class ClassPathHacker {

private static final Class[] parameters = new Class[]{URL.class};

public static void addFile(String s) throws IOException {
   File f = new File(s);
   addFile(f);
}//end method

public static void addFile(File f) throws IOException {
   addURL(f.toURI().toURL());
}//end method


public static void addURL(URL u) throws IOException {

  URLClassLoader sysloader = (URLClassLoader) ClassLoader.getSystemClassLoader();
  Class sysclass = URLClassLoader.class;

  try {
     Method method = sysclass.getDeclaredMethod("addURL", parameters);
     method.setAccessible(true);
     method.invoke(sysloader, new Object[]{u});
  } catch (Throwable t) {
     t.printStackTrace();
     throw new IOException("Error, could not add URL to system classloader");
  }//end try catch

   }//end method

}//end class

with the property loader file of

import java.io.InputStream;
import java.util.Enumeration;
import java.util.Locale;
import java.util.Properties;
import java.util.ResourceBundle;


public abstract class PropertyLoader
{
    /**
     * Looks up a resource named 'name' in the classpath. The resource must map
     * to a file with .properties extention. The name is assumed to be absolute
     * and can use either "/" or "." for package segment separation with an
     * optional leading "/" and optional ".properties" suffix. Thus, the
     * following names refer to the same resource:
     * <pre>
     * some.pkg.Resource
     * some.pkg.Resource.properties
     * some/pkg/Resource
     * some/pkg/Resource.properties
     * /some/pkg/Resource
     * /some/pkg/Resource.properties
     * </pre>
     * 
     * @param name classpath resource name [may not be null]
     * @param loader classloader through which to load the resource [null
     * is equivalent to the application loader]
     * 
     * @return resource converted to java.util.Properties [may be null if the
     * resource was not found and THROW_ON_LOAD_FAILURE is false]
     * @throws IllegalArgumentException if the resource was not found and
     * THROW_ON_LOAD_FAILURE is true
     */
    public static Properties loadProperties (String name, ClassLoader loader)
    {
        if (name == null)
            throw new IllegalArgumentException ("null input: name");

        if (name.startsWith ("/"))
            name = name.substring (1);

        if (name.endsWith (SUFFIX))
            name = name.substring (0, name.length () - SUFFIX.length ());

        Properties result = null;

        InputStream in = null;
        try
        {
            if (loader == null) loader = ClassLoader.getSystemClassLoader ();

            if (LOAD_AS_RESOURCE_BUNDLE)
            {    
                name = name.replace ('/', '.');
                // Throws MissingResourceException on lookup failures:
                final ResourceBundle rb = ResourceBundle.getBundle (name,
                    Locale.getDefault (), loader);

                result = new Properties ();
                for (Enumeration keys = rb.getKeys (); keys.hasMoreElements ();)
                {
                    final String key = (String) keys.nextElement ();
                    final String value = rb.getString (key);

                    result.put (key, value);
                } 
            }
            else
            {
                name = name.replace ('.', '/');

                if (! name.endsWith (SUFFIX))
                    name = name.concat (SUFFIX);

                // Returns null on lookup failures:
                in = loader.getResourceAsStream(name);
                if (in != null)
                {
                    result = new Properties ();
                    result.load (in); // Can throw IOException
                }
            }
        }
        catch (Exception e)
        {
            result = null;
        }
        finally
        {
            if (in != null) try { in.close (); } catch (Throwable ignore) {}
        }

        if (THROW_ON_LOAD_FAILURE && (result == null))
        {
            throw new IllegalArgumentException ("could not load [" + name + "]"+
                " as " + (LOAD_AS_RESOURCE_BUNDLE
                ? "a resource bundle"
                : "a classloader resource"));
        }

        return result;
    }

    /**
     * A convenience overload of {@link #loadProperties(String, ClassLoader)}
     * that uses the current thread's context classloader.
     */
    public static Properties loadProperties (final String name)
    {
        return loadProperties (name,
            Thread.currentThread ().getContextClassLoader ());
    }

    private static final boolean THROW_ON_LOAD_FAILURE = true;
    private static final boolean LOAD_AS_RESOURCE_BUNDLE = false;
    private static final String SUFFIX = ".properties";
} // End of class

then you can add a path as follows

 try {
            //First Load up the properties and populate the config
            ClassPathHacker.addFile("/pathtomyapp");
        } catch (IOException ex) {
            ex.printStackTrace();
        }
        properties = PropertyLoader.loadProperties("myapp");

or you can also use getResourceBundle to get your resources, this is just one example of hacking the classpath to allow files to be available, you can always just add the classpath programatically and let the jar files you need to be available to reside there, so if you always ensure that the app network path is Q: you can add Q:\ to the classpath.