jQuery to PHP - serialized strings

Question

I'm currently AJAX'ing a login form.

var data = $(this).serialize();

This is the data I'm sending, I get this with PHP using Codeigniter like so:

$ajax = $this->input->post('data');

This returns username=john&password=doe as you'd expect.

How do I turn that into an array? I've tried doing unserialize() and I get null.

possibly answer of your question [here](http://stackoverflow.com/a/3817220/388053) — Muhammad Saifuddin, Nov 29 '11 at 21:56

score 4 · Accepted Answer · answered Nov 29 '11 at 21:36

4

I believe you can use PHP's parse_str() function: http://php.net/manual/en/function.parse-str.php

<?php
$str = "first=value&arr[]=foo+bar&arr[]=baz";
parse_str($str);
echo $first;  // value
echo $arr[0]; // foo bar
echo $arr[1]; // baz

parse_str($str, $output);
echo $output['first'];  // value
echo $output['arr'][0]; // foo bar
echo $output['arr'][1]; // baz

?>

Using your code it would be:

parse_str($this->input->post('data'), $ajax);
echo $ajax['username'] . "/" . $ajax['password'];

answered Nov 29 '11 at 21:36

Jasper

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Maybe give it another try, I just tried the demo and it worked as expected. – Jasper Nov 29 '11 at 21:39
Eugh, it was a typo on my `parse_str` before! – daryl Nov 29 '11 at 21:40

Francis Avila · Answer 2 · 2011-11-29T21:49:56.367

Short answer is with parse_str;

parse_str($ajax, $array);
$array === array('username'=>'john', 'password'=>'doe');

However, the way you send your ajax data is a bit odd. Why are you serializing to a formencoded string and sending that string as a value to the 'data' parameter? Why don't you just send it directly? Then you could use $this->input->post('username') === 'john' without the extra level of deserializing.

For example, do this:

$.post(url, $(form).serialize());

instead of this (which you seem to be doing:

$.post(url, {data:$(form).serialize()});

score 1 · Answer 3 · answered Nov 29 '11 at 21:37

1

Use parse_str()

http://php.net/manual/en/function.parse-str.php

answered Nov 29 '11 at 21:37

Jordan Brown

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score 1 · Answer 4 · answered Nov 29 '11 at 21:38

1

$parameters = array();

foreach ( explode( '&', $ajax ) as $parameterAndValue ) {
    list ( $parameter, $value ) = explode( '=', $parameterAndValue );
    $parameters[$parameter] = $value;
}

answered Nov 29 '11 at 21:38

George Cummins

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score 0 · Answer 5 · answered Jan 24 '13 at 10:04

0

Simply use as follows

<?php $username = $this->input->post('username');?>
<?php $password= $this->input->post('password');?>

You can do anything with above variables

answered Jan 24 '13 at 10:04

Srihari Goud

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score 0 · Answer 6 · answered Dec 11 '11 at 09:34

I guest we could use normal request, it's defend on the request type from ajax, using GET or POST, and then in the php we could use like normal post, like $_POST['username'] or $_GET['username'] we don't have to use function to unserialize that, and for validation using CI just call like normal use, $this->input->post('username'),am i wrong ?

jQuery to PHP - serialized strings

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