How to get current date and time?

Question

How to get current date d/m/y. I need that they have 3 different variables not one, for example day=d; month=m; year=y;.

What have you tried? http://stackoverflow.com/questions/997946/c-get-current-time-and-date — daniloquio, Dec 01 '11 at 15:20

score 29 · Accepted Answer · edited Aug 28 '13 at 19:39

29

For linux, you would use the 'localtime' function.

#include <time.h>

time_t theTime = time(NULL);
struct tm *aTime = localtime(&theTime);

int day = aTime->tm_mday;
int month = aTime->tm_mon + 1; // Month is 0 - 11, add 1 to get a jan-dec 1-12 concept
int year = aTime->tm_year + 1900; // Year is # years since 1900

edited Aug 28 '13 at 19:39

answered Dec 01 '11 at 15:23

Anya Shenanigans

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Did you mean localtime(&time(NULL)); ? – maximus Feb 01 '13 at 02:53
I corrected the answer as it would not compile as-is. You can't an rvalue by pointer (i.e. just a number) so you need to put it into a variable first – Anya Shenanigans Feb 01 '13 at 11:01

sehe · Answer 2 · 2015-09-10T12:36:24.870

17

Here is the chrono way (C++0x) - see it live on http://ideone.com/yFm9P

#include <chrono>
#include <ctime>
#include <iostream>

using namespace std;

typedef std::chrono::system_clock Clock;

int main()
{
    auto now = Clock::now();
    std::time_t now_c = Clock::to_time_t(now);
    struct tm *parts = std::localtime(&now_c);

    std::cout << 1900 + parts->tm_year  << std::endl;
    std::cout << 1    + parts->tm_mon   << std::endl;
    std::cout <<        parts->tm_mday  << std::endl;

    return 0;
}

edited Sep 10 '15 at 12:36

answered Dec 01 '11 at 15:38

sehe

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posted the working example live on http://ideone.com/yFm9P – sehe Dec 01 '11 at 15:52
@PaoloM that header is required for [`std::time_t`](http://en.cppreference.com/w/cpp/chrono/c/time_t) – sehe Sep 10 '15 at 12:36
Sorry, under gcc 4.8 it compiles without ``. It gets included by `` for sure. – Paolo M Sep 10 '15 at 12:43

score 2 · Answer 3 · edited May 23 '17 at 12:25

2

The ctime library provide such functionnality.

Also check this. It is an other post that might help you out depending on your platform.

edited May 23 '17 at 12:25

Community

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answered Dec 01 '11 at 15:22

TurnsCoffeeIntoScripts

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`#include #include using namespace std; int main() { time_t t = time(0); // get time now struct tm * now = localtime( & t ); cout << (now->tm_year + 1900) << '-' << (now->tm_mon + 1) << '-' << now->tm_mday << endl; } ` Thanks – Wizard Dec 01 '11 at 15:34

How to get current date and time?

3 Answers3