If MyClass
implements IEquatable<MyClass>
, then try this:
expected.Sort();
actual.Sort();
if (Enumerable.SequenceEqual(actual, expected)) { ... }
If it does not implement IEquatable
then you could expect strange behavior, since the object references will be compared in the two lists, and not their fields:
using System;
using System.Collections.Generic;
using System.Linq;
public class MyClassA
{
private int i;
public MyClassA(int i) { this.i = i; }
}
public class MyClassB : IEquatable<MyClassB>
{
private int i;
public MyClassB(int i) { this.i = i; }
public bool Equals(MyClassB other) { return this.i == other.i; }
}
public class Program
{
public static void Main()
{
var actual1 = new List<MyClassA>() { new MyClassA(1), new MyClassA(2), new MyClassA(3) };
var expected1 = new List<MyClassA>() { new MyClassA(1), new MyClassA(2), new MyClassA(3) };
Console.WriteLine(Enumerable.SequenceEqual(actual1, expected1));
var a1 = new MyClassA(1);
var a2 = new MyClassA(2);
var a3 = new MyClassA(3);
var actual2 = new List<MyClassA>() { a1, a2, a3 };
var expected2 = new List<MyClassA>() { a1, a2, a3 };
Console.WriteLine(Enumerable.SequenceEqual(actual2, expected2));
var actual3 = new List<MyClassB>() { new MyClassB(1), new MyClassB(2), new MyClassB(3) };
var expected3 = new List<MyClassB>() { new MyClassB(1), new MyClassB(2), new MyClassB(3) };
Console.WriteLine(Enumerable.SequenceEqual(actual3, expected3));
var actual4 = new List<MyClassB>() { new MyClassB(1), new MyClassB(2), new MyClassB(3) };
var expected4 = new List<MyClassB>() { new MyClassB(3), new MyClassB(2), new MyClassB(1) };
Console.WriteLine(Enumerable.SequenceEqual(actual4, expected4));
}
}
Output:
False
True
True
False