How to get full path from savefiledialog and use in "startInfo.Arguments"?

Question

In my case the SaveFileDialog will not write any file, but I want to use to specify the path for a command line app which will create the logfile on the same location as "saved" in the sf dialog.

SaveFileDialog sfd = new SaveFileDialog();
sfd.Filter = "*.txt";
string sfdname = saveFileDialog1.FileName;
if (sfd.ShowDialog() == DialogResult.OK)
{
  Path.GetFileName(sfd.FileName);
}

startInfo.Arguments = "--log=" + Path.GetFileName(sfd.FileName);

Wanderson López · Answer 1 · 2015-10-29T23:13:44.533

16

You can use

Path.GetFullPath(sfd.FileName);

Instead of

Path.GetFileName(sfd.FileName);

Complete version...

SaveFileDialog sfd = new SaveFileDialog();
sfd.Filter = "*.txt";
string sfdname = saveFileDialog1.FileName;
if (sfd.ShowDialog() == DialogResult.OK)
{
  Path.GetFullPath(sfd.FileName);
}

startInfo.Arguments = "--log=" + Path.GetFullPath(sfd.FileName);

edited Oct 29 '15 at 23:13

answered Oct 29 '15 at 23:08

Wanderson López

261
2
5

Daniel Hilgarth · Accepted Answer · 2011-12-08T13:15:55.903

6

Just remove the Path.GetFileName:

startInfo.Arguments = "--log=\"" + sfd.FileName + "\"";

edited Dec 08 '11 at 13:15

answered Dec 07 '11 at 14:28

Daniel Hilgarth

171,043
40
335
443

With this I get the full path of the file (I checked with a textbox) but the command line app don't recognize it. – user830054 Dec 07 '11 at 14:50
@user830054: Try adding quotes around the path. See updated answer. – Daniel Hilgarth Dec 08 '11 at 13:16

royhette agapito · Answer 3 · 2017-10-16T14:59:39.170

2

OpenFileDialog openFileDialog1 = new OpenFileDialog();
                openFileDialog1.Filter = "Image files | *.jpg";
                if (openFileDialog1.ShowDialog() == DialogResult.OK)
                {
                 employee_dp.Image = Image.FromFile(openFileDialog1.FileName);
                 string path = System.IO.Path.GetDirectoryName(openFileDialog1.FileName);
                 string onlyFileName = System.IO.Path.GetFileName(openFileDialog1.FileName);
                 filepath = Path.GetFullPath(path).Replace(@"\", @"\\");
                 filepath = filepath + "\\\\" + onlyFileName;
                 MessageBox.Show(filepath);

edited Oct 16 '17 at 14:59

answered Oct 16 '17 at 12:21

royhette agapito

21
2

What is that `*`? – Maciej Jureczko Oct 16 '17 at 12:46
typo sorry hehehe – royhette agapito Oct 16 '17 at 15:03

score 2 · Answer 4 · answered Dec 07 '11 at 16:57

I think you are using the wrong dialog form based on what you are describing.

Try using the FolderBrowserDialog class:

string folderPath = string.Empty;

using (FolderBrowserDialog fdb = new FolderBrowserDialog()) {
  if (fdb.ShowDialog() == DialogResult.OK ){
    folderPath = fdb.SelectedPath;
  }
}

if (folderPath != string.Empty) {
  startInfo.Arguments = "--log=" + folderPath;
}

score 0 · Answer 5 · answered Dec 27 '12 at 07:54

0

The problem might be using the wrong FileSaveDialog.
The one in Win32.dll doesn't provide the full path, but the one in System.Windows.Forms does.

answered Dec 27 '12 at 07:54

Noich

14,631
15
62
90

score 0 · Answer 6 · answered Dec 07 '11 at 14:28

0

Perhaps Path.GetFullPath would help?

answered Dec 07 '11 at 14:28

oleksii

35,458
16
93
163

How to get full path from savefiledialog and use in "startInfo.Arguments"?

6 Answers6