How to skip outer loop in ruby?

Question

Possible Duplicate:
How to break outer cycle in Ruby?

array_1 = %W(http://www.abc.com www.xyz.com www.pqr.com)
array_2 = %W(www.abc.com www.exmple.com)
array_1.each do |a1|
  array_2.each do |a2|
    next if(a1.include?(a2))
  end
puts a1
end

I want to skip those entries which are present in array_2. Is there anyway I can skip printing a1 if condition is satisfied? Ruby doesn't have label like java and I want to skip outer loop. :(

Any help would be great

I don't think the question is duplicate; while the OP is indeed asking about how to break an outer cycle, refactoring seems the way to go. — tokland, Dec 08 '11 at 11:38
@tokland code snippet works perfectly in my actual implementation. Thanks all for replying :) — benchwarmer, Dec 08 '11 at 12:27

score 4 · Accepted Answer · answered Dec 08 '11 at 11:35

4

You can write:

array_1.each do |a1|
  next if array_2.any? { |a2| a1.include?(a2) }
  ...
end

answered Dec 08 '11 at 11:35

tokland

66,169
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score 1 · Answer 2 · answered Dec 08 '11 at 11:12

1

You can pass lambda with return statement to each method instead of block. Lambda function will return value, not the method enclosing lambda.

array_1 = %W(http://www.abc.com www.xyz.com www.pqr.com)
array_2 = %W(www.abc.com www.exmple.com)
array_1.each(&lambda do |a1|
  array_2.each do |a2|
    return if(a1.include?(a2))
  end
  puts a1
end)

answered Dec 08 '11 at 11:12

Aliaksei Kliuchnikau

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4
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break will exit the current loop, but return will exit a function. so putting that in a function like Alex is a good way to do it. in other languages you'd be able to use the evil goto :) – Joseph Le Brech Dec 08 '11 at 11:17

score 1 · Answer 3 · answered Dec 08 '11 at 12:14

Instead of trying to mimic other languages, you can do something like this instead:

array_1.product(array_2).each do |a1, a2|
  next if(a1.include?(a2))
end

or, more idiomatic:

array_1.product(array_2).reject{ |a1, a2|
  a1.include?(a2)
}.each{ |a1, a2|
  # do something here
}

steenslag · Answer 4 · 2011-12-08T15:46:22.807

1

[Edit]Misread the input. This should be better. The any? method quits searching if one match is found.

array_1 = %W(http://www.abc.com www.xyz.com www.pqr.com)
array_2 = %W(www.abc.com www.exmple.com)

puts array_1.reject{|a1| array_2.any?{|a2| a1.include?(a2)} }

But if you insist in breaking out of a loop, there is catchand throw:

array_1.each do |a1|
  catch :its_in do
    array_2.each do |a2|
      throw :its_in if(a1.include?(a2))
    end
  puts a1
  end
end

edited Dec 08 '11 at 15:46

answered Dec 08 '11 at 12:23

steenslag

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1

substraction of arrays is a good idea, but look at the values, the OP really needs test inclusion, they are not equal. – tokland Dec 08 '11 at 15:10

score 0 · Answer 5 · answered Dec 08 '11 at 11:19

0

You could use a while loop

This might work:

busy = true
while busy
  array1.each do |a1|
    array2.each do |a2|

       busy = false
    end
  end
end

answered Dec 08 '11 at 11:19

Joseph Le Brech

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How to skip outer loop in ruby?

5 Answers5