Batch file to open new file in directory?

Question

I have in C:\files\ for example the following files:

apple.txt
orange.doc
banana.exe
kiwi.avi

And I place e.g. mango.exe in there.

What script or technique can I use to be notified immediately of the change to this folder and to open the file immediately?

score 1 · Accepted Answer · edited May 23 '17 at 11:46

1

For a batch file, this answer may help:

You would need to extend the solution there yourself to launch the detected changes.

In C# this can be done quite easily. This question: How can I monitor a Windows directory for changes? is similar.

edited May 23 '17 at 11:46

Community

answered Dec 09 '11 at 15:38

xan

Thanks man you made my day ;) I got: @echo off if not exist c:\OldDir.txt echo. > c:\OldDir.txt dir /b "d:\My Folder" > c:\NewDir.txt set equal=no fc c:\OldDir.txt c:\NewDir.txt | find /i "no differences" > nul && set equal=yes copy /y c:\Newdir.txt c:\OldDir.txt > nul if %equal%==yes goto :eof rem Your batch file lines go here – mojamoja Dec 09 '11 at 15:48
Actually, how do I run it? I still can't see how this script knows that mango.exe is the new one? – mojamoja Dec 09 '11 at 16:22

score 0 · Answer 2 · answered Dec 09 '11 at 15:02

0

move \wherever\mango.exe c:\files\mango.exe
start mango.exe

answered Dec 09 '11 at 15:02

Marc B

I think they want to watch the directory for changes and as soon as a new file is detected it should be opened. – Joey Dec 09 '11 at 15:04
@ Joey Exactly, can you please help me out? – mojamoja Dec 09 '11 at 15:28

2 Answers2