Solving 'Argument #2 should be an array in'

Question

I'm working with the following code kindly supplied in an answer here but it generates the following errors

Warning: array_map() [function.array-map]: Argument #2 should be an array in [path/to] on [Line #]

and

'Warning: Wrong parameter count for array_intersect() in [path/to] on [line #]'

Googleing the errors has produced no useful ideas - any help appreciated.

<?php
$types = array('.pdf', '.doc', '.xls');
if(0 < count(array_intersect(array_map('strtolower', $filename, $types)))) {
   echo 'One';
} else {
   echo 'Two';
}
?>

//update

<?php
$filename = array(get_post_meta(get_the_ID(), 'mjwlink-url'));
$types = array('.pdf', '.doc', '.xls');
if(0 < count(array_intersect(array_map('strtolower', $filename), $types))) {
   echo 'One';
} else {
   echo 'Two';
}

?>

(After OP's update) Do you still get the error? – Grzegorz Rożniecki Dec 11 '11 at 02:23 — Grzegorz Rożniecki, Dec 11 '11 at 02:23

score 2 · Accepted Answer · answered Dec 11 '11 at 02:07

2

strtolower takes exactly one argument, while array_map with three arguments ($fun, $arr1, $arr2) takes function fun, which must take two arguments itself: fun(arg1, arg2). Look at Example #3 in array_maps docs page.

PS $filename variable is not initialized in your code?

EDIT: You probably want array_intersect(array_map('strtolower', $filename), $types) instead (you put bracket in wrong place)...

answered Dec 11 '11 at 02:07

Grzegorz Rożniecki

27,415
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I've fixed the problems as you suggested and the code now executes, but doesn't perform it's purpose - all urls, even those ending in doc, pdf etc output condition two. Any further help would be appreciated. – toomanyairmiles Dec 11 '11 at 02:27
Can you print `$filename`'s contents? – Grzegorz Rożniecki Dec 11 '11 at 02:29
Interesting, it literally prints the word 'Array'! – toomanyairmiles Dec 11 '11 at 02:31
Even after printing contents with [`var_dump`](http://php.net/manual/en/function.var-dump.php)? Does `get_post_meta` return correct value then? – Grzegorz Rożniecki Dec 11 '11 at 02:35
'var_dump' prints array(1) { [0]=> array(1) { [0]=> string(36) "http://www.prisonreformtrust.org.uk/" } } – toomanyairmiles Dec 11 '11 at 02:42

score 0 · Answer 2 · answered Dec 11 '11 at 02:07

0

For array_map the second argument needs to be an array, so I guess you should be passing $types there and not $filename.

Also, you need to pass at least two arrays into array_intersect. You're actually only passing one there.

answered Dec 11 '11 at 02:07

Darragh Enright

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Solving 'Argument #2 should be an array in'

2 Answers2