You can't use StreamReader because it is meant to read streams in which the bytes are in the UTF8. Instead, you want to read the contents of the stream to a receive buffer, remove all the stuff you don't need, get the file extension of the uploaded file, extract the contents of the uploaded file, then save the file contents to a new file. The code I show in this post assumes your form looks like this:
<form enctype="multipart/form-data" method="POST" action="/uploader">
<input type="file" name="file">
<input type="submit">
</form>
As you can see, the code is only meant to handle a form that only has the file. Since there is no way to extract the contents of a file on the server from a application/x-www-form-urlencoded form, so you have to include the "multipart/form-data".
First, for this method of handling uploaded files, you will first need this little bit of code:
using System;
using System.IO;
using System.Text;
using System.Net;
using System.Collections.Generic;
Second, you need to read the contents of the request.InputStream to a receive buffer, or a byte[]. We do this by making a byte[] buffer with the length of the Content-Length header sent by the browser. Then, we read the contents of the request.InputStream to the buffer. The code would look like this:
int len = int.Parse(request.Headers["Content-Length"]);
byte[] buffer = new byte[len];
request.InputStream.Read(buffer, 0, len);
The stream will look somewhat like this:
------WebKitFormBoundary9lcB0OZVXSqZLbmv
Content-Disposition: form-data; name="file"; filename="example-file.txt"
Content-Type: text/plain
file contents here
------WebKitFormBoundary9lcB0OZVXSqZLbmv--
Next, you need to get the file extension of the uploaded file. We can do this using this code:
string fileExtension = Encoding.UTF8.GetString(bytes).Split("\r\n")[1].Split("filename=\"")[1].Replace("\"", "").Split('.')[^1];
Then, we need to get the contents of the file. We do this by removing the stuff at the beginning (the -----WebKitFormBoundary, the Content-Disposition, the Content-Type, and a blank line), then removing the last line of the request body, plus an extra \r\n at the end. Here is the code that does just that:
// note that the variable buffer is the byte[], and the variable bytes is the List<byte>
string stringBuffer = Encoding.UTF8.GetString(buffer);
List<byte> bytes = new List<byte>(buffer);
string[] splitString = stringBuffer.Split('\n');
int lengthOfFourLines = splitString[0].Length + splitString[1].Length +
splitString[2].Length + splitString[3].Length + 4;
bytes.RemoveRange(0, lengthOfFourLines);
int lengthOfLastLine = splitString[^2].Length+2;
bytes.RemoveRange(bytes.Count - lengthOfLastLine, lengthOfLastLine);
buffer = bytes.ToArray();
Finally, we need to save the contents to a file. The code below generates a random file name with the user-specified file extension, and saves the files contents to it.
string fname = "";
string[] chars = "q w e r t y u i o p a s d f g h j k l z x c v b n m Q W E R T Y U I O P A S D F G H J K L Z X C V B N M 1 2 3 4 5 6 7 8 9 0".Split(" ");
for (int i = 0; i < 10; i++)
{
fname += chars[new Random().Next(chars.Length)];
}
fname += fileExtension;
FileStream file = File.Create(fname);
file.Write(buffer);
file.Close();
Here is the whole code put together:
public static void Main()
{
var listener = new HttpListener();
listener.Prefixes.Add("http://localhost:8080/");
listener.Start();
while(true)
{
HttpListenerContext context = listener.GetContext();
HttpListenerRequest request = context.Request;
HttpListenerResponse response = context.Response;
if(request.HttpMethod=="POST") SaveFile(request);
response.OutputStream.Write(Encoding.UTF8.GetBytes("file successfully uploaded"));
response.OutputStream.Close();
}
}
void SaveFile(HttpListenerRequest request)
{
int len = (int)request.ContentLength64;
Console.WriteLine(len);
byte[] buffer = new byte[len];
request.InputStream.Read(buffer, 0, len);
string stringBuffer = Encoding.UTF8.GetString(buffer);
Console.WriteLine(stringBuffer.Replace("\r\n","\\r\\n\n"));
string fileExtension = stringBuffer.Split("\r\n")[1]
.Split("filename=\"")[1]
.Replace("\"", "")
.Split('.')[^1]
;
List<byte> bytes = new List<byte>(buffer);
string[] splitString = stringBuffer.Split('\n');
int lengthOfFourLines = splitString[0].Length + splitString[1].Length + splitString[2].Length + splitString[3].Length + 4;
bytes.RemoveRange(0, lengthOfFourLines);
int lengthOfLastLine = splitString[^2].Length+2;
bytes.RemoveRange(bytes.Count - lengthOfLastLine, lengthOfLastLine);
buffer = bytes.ToArray();
string fname = "";
string[] chars = "q w e r t y u i o p a s d f g h j k l z x c v b n m Q W E R T Y U I O P A S D F G H J K L Z X C V B N M 1 2 3 4 5 6 7 8 9 0".Split(" ");
for (int i = 0; i < 10; i++)
{
fname += chars[new Random().Next(chars.Length)];
}
fname += "." + fileExtension;
FileStream file = File.Create(fname);
file.Write(buffer);
file.Close();
}
Also, if you want to send an uploaded file to the client, here is a useful function that sends the file to the client.
// Make sure you are using System.IO, and System.Net when making this function.
// Also make sure you set the content type of the response before calling this function.
// fileName is the name of the file you want to send to the client, and output is the response.OutputStream.
public static void SendFile(string fileName, Stream output)
{
FileStream fs = new FileStream(fileName, FileMode.Open, FileAccess.Read);
fs.CopyTo(output);
fs.Close();
output.Close();
}
