How to Split ( " ) Using Regex in Java

Question

I'm new in Java I have a string which is get by StringBuilder from a HTML file, and I had split it numerous step, and now I put it into a String, lets called it alink

aLink is a String which contain <a href="http//www.google.com">Google</a>

I want to use method .split(String regex) in Java, so that I can get http://www.google.com and put it into a String variable.

My question is, how to do it, because i cannot put " into my parameter.

Thank you

put an example aLink. You can escape special chars in Java like \\" — hovanessyan, Dec 14 '11 at 16:55
Duplicate of http://stackoverflow.com/questions/60160/how-to-escape-text-for-regular-expression-in-java — Tetsujin no Oni, Dec 14 '11 at 16:56
Why don't you use a `Pattern` and a `Matcher` to get the URL instead of using split? — Fred, Dec 14 '11 at 17:00

score 9 · Accepted Answer · answered Dec 14 '11 at 16:54

9

Use \ to escape special characters:

string.split("\"");

answered Dec 14 '11 at 16:54

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How to Split ( " ) Using Regex in Java

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