Releasing an NSTimer iPhone?

Question

I have an NSTimer declared in my .h and in the viewDidLoad of the /m I have the code:

timer = [NSTimer scheduledTimerWithTimeInterval:kComplexTimer target:self selector:@selector (main) userInfo:nil repeats:YES];

I also have [timer release]; in my dealloc.

However when I exit the view and return to it, the timer has not in fact released, it has doubles in speed! How do I solve this & what am I doing wrong???

Thanks

score 6 · Answer 1 · answered Dec 17 '11 at 16:56

6

you don't need to release it as you have not retained it - as a rule. all you need to do is just call [timer invalidate]; which will stop your timer.

answered Dec 17 '11 at 16:56

Saurabh Passolia

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score 3 · Accepted Answer · answered Apr 14 '12 at 11:25

3

Nice Answer , but good to check whether the time is nil or not to avoid unwanted exception..

if( timer ! = nil )
{
  [timer invalidate];
  timer = nil;
}

Thank you...

answered Apr 14 '12 at 11:25

jillu_

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score 2 · Answer 3 · answered Dec 17 '11 at 16:58

2

[timer invalidate];
timer = nil;

The second line is important if you want to reset the NSTimer

answered Dec 17 '11 at 16:58

Fabio Poloni

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+1 The `nil` is very key. I used to have issues with timers and their reuse until adding that part. – dredful Dec 17 '11 at 17:13

score 1 · Answer 4 · answered Dec 17 '11 at 17:04

You must not call release on a object that it not be created by "new", "alloc", "retain", "copy".

In this case, you had created a Timer by scheduledTimerWithTimeInterval method, So you must not call release method but call [timer invalidate] to stop the timer.

Releasing an NSTimer iPhone?

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