Python 2.5 convert string to binary

Question

I know this is easily possible in python 2.6. But what is the easiest way to do this in Python 2.5?

x = "This is my string"
b = to_bytes(x)  # I could do this easily in 2.7 using bin/ord 3+ could use b"my string"
print b

Any suggestions? I want to take the x and turn it into

00100010010101000110100001101001011100110010000001101001011100110010000001101101011110010010000001110011011101000111001001101001011011100110011100100010

Is your 'xml string' really a str() and not a unicode() object? — , Dec 18 '11 at 18:34
Its an str(). Formed almost exactly as above, I could make it unicode.. — Nix, Dec 18 '11 at 20:18
related: [Convert Binary to ASCII and vice versa](http://stackoverflow.com/q/7396849/4279) — jfs, Mar 12 '14 at 11:00

kev · Accepted Answer · 2012-01-11T10:36:34.727

7

This one-line works:

>>> ''.join(['%08d'%int(bin(ord(i))[2:]) for i in 'This is my string'])
'0101010001101000011010010111001100100000011010010111001100100000011011010111100100100000011100110111010001110010011010010110111001100111'

EDIT

You can write bin() yourself

def bin(x):
    if x==0:
        return '0'
    else:
        return (bin(x/2)+str(x%2)).lstrip('0') or '0'

edited Jan 11 '12 at 10:36

answered Jan 10 '12 at 15:45

kev

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@Nix You can write `bin()` yourself – kev Jan 11 '12 at 10:36

score 1 · Answer 2 · answered Sep 26 '13 at 09:21

I think you could do it in a cleaner way like this:

>>>''.join(format(ord(c), '08b') for c in 'This is my string')
'0101010001101000011010010111001100100000011010010111001100100000011011010111100100100000011100110111010001110010011010010110111001100111'

the format function will represent the character in a 8 digits, binary representation.

Python 2.5 convert string to binary

2 Answers2

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