Notepad++ regular expression for XML replace

Question

I need to replace following lines in XML file:

hashName="'Miecz Nieb. Wojownika+5IMiecz Nieb. Wojownika+5" name="Miecz Nieb. Wojownika+5"

As the above line is not correct, I want it to be replaced like this:

hashName="'Miecz Nieb. Wojownika+5'" name="Miecz Nieb. Wojownika+5"

(It should take the item name from the name="" attr!).

This is what I got at the moment, its not working as expected since it does remove my name="..." attribute.

Search for:

hashName="(')(.*)"(.)name="(.*)"(.)/

Replace with:

hashName="'\4'" name="\4"

[On parsing XML or HTML with regular expressions](http://stackoverflow.com/questions/1732348/regex-match-open-tags-except-xhtml-self-contained-tags) — Benoit, Dec 19 '11 at 07:37
You have a dot in your regex after the last quote, but since the final quote in the input is at the end, with nothing behind it, that won't match. — Mr Lister, Dec 19 '11 at 07:44

score 1 · Answer 1 · answered Dec 19 '11 at 07:45

1

This should work

Search for: hashName=\".+\" name=\"(.+)\"
Replace with: hashName="'\1'" name="\1"

answered Dec 19 '11 at 07:45

denis.solonenko

score 1 · Accepted Answer · answered Dec 19 '11 at 07:53

For this simple example this is working

Search for

hashName="[^"]*"\s*name="([^"]*)"

and replace with

hashName="'\1'" name="\1"

If you don't want to capture or group characters, don't put brackets around it, therefor I removed most of them.

To avoid that too much is matched, e.g. if you have two "name" attributes in one row, I used [^"]* to do a non greedy matching.

2 Answers2