Nested Macro : Order of Expansion

Question

Possible Duplicate:
Why i am not getting the expected output in the following c programme?

i am having a doubt in order of evaluation of macros.like for the following code i am not able to understand the ouput:

#include <stdio.h>
#define f(a,b) a##b
#define g(a) #a
#define h(a) g(a) 
int main()
{
    printf("%s\n",h(f(1,2)));
    printf("%s\n",g(f(1,2)));
    return 0;
}

Output

12
f(1,2)

why not f is getting expanded first before g in the second printf ?

This (exact!) question was asked here more than once. – MByD Dec 19 '11 at 10:30 — MByD, Dec 19 '11 at 10:30
thnx guys...got my answer from the duplicate posts.. :) – Amol Sharma Dec 19 '11 at 10:39 — Amol Sharma, Dec 19 '11 at 10:39

score 0 · Accepted Answer · answered Dec 19 '11 at 10:37

0

It's a consequence of how macros are expanded, and has an impact on self-referential macros... This is quite nicely explained in detail in the GNU CPP manual

answered Dec 19 '11 at 10:37

Ahmed Masud

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Nested Macro : Order of Expansion

1 Answers1