regular expression to add characters before and after numbers

Question

I have a list of numbers between square brackets, and I need to add words before and after the exact numbers (i.e. keep the same numbers). I use notepad++ to replace, but if you have a solution with other program please advise.

Example:

text [121] othertext
moretext [16] othertextmore
andtext [5940] othertextplus

outcome:

text xxxxxxxxx [121] xxxxxxxxx othertext
moretext xxxxxxxxx [16] xxxxxxxxx othertextmore
andtext xxxxxxxxx [5940] xxxxxxxxx othertextplus

The numbers are of course \d+ but I want to tell it to keep the same numbers when looking.

While the regex sill stay the same, the code will change: WHich Language? — Eugen Rieck, Dec 24 '11 at 10:48

score 25 · Accepted Answer · answered Dec 24 '11 at 10:49

25

Find What: (\[\d+])

Replace With: xxxxxxxxx \1 xxxxxxxxx

enter image description here

answered Dec 24 '11 at 10:49

manojlds

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@Mike - You can accept as answer by clicking on the tick on the left. – manojlds Dec 24 '11 at 10:53
No need for parentheses if you're going to use the entire match anyway - replace with `xxxxxx \0 xxxxxx`. – Tim Pietzcker Dec 24 '11 at 10:56
1

Really? Interesting but not surprising given Notepad++'s lackluster regex support. – Tim Pietzcker Dec 24 '11 at 11:11
1

don't forget to put your search statement into parenthesis – JinSnow Dec 15 '16 at 06:06

score 5 · Answer 2 · answered Jul 05 '17 at 10:05

5

Regular expression:

Find regex = \[\d+\]
Replace regex = xxxxxxxxx$&xxxxxxxxx

Refer: regexr

answered Jul 05 '17 at 10:05

Mukul Aggarwal

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score 2 · Answer 3 · answered Dec 24 '11 at 10:53

2

C#:

line=Regex.Replace(line,@"([^\[])(\[\d+\])(.*)","$1xxxxxxxxx $2 xxxxxxxxx$3");

Other languages analogous

answered Dec 24 '11 at 10:53

Eugen Rieck

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regular expression to add characters before and after numbers

3 Answers3

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