How to match all words that contain a given digit?

Question

I'm wondering how to match all words that contain a given digit?

I've looked at O'Reilly Regular Expressions Cookbook, but failed to get the idea.

Case 1. Some characters are in front of the digit.(Solved)

\b(\d+[^\s]+)\b

time=>123, address~4321

Case 2. Some characters are followed by digit.(Solved)

\b(\d+[^\s]+)\b

1234<=range, 321=>location

Case 3. Some characters are forth digit.

time~1325@range, address*4321%location

Case 4. Duplicate in a single line of Case1 or Case2 or Case3.

firstTime=12   secondTime=34 
429923<=firstRange                353534=>secondRange
A12345alpha      B9876beta

What do you call a "word"? Any character sequence with no space? — fge, Dec 28 '11 at 20:17
Also see https://stackoverflow.com/questions/2491930/is-there-an-online-regexbuddy-like-regular-expression-analyzer — Christophe Roussy, Mar 26 '18 at 09:46

npinti · Answer 1 · 2011-12-28T21:10:04.813

0

Since you have defined a word to be any string that does not contain a white space, you might want to use something like this:

([^\s]*\d+.[^\s]*)\m

The \m flag should make the regex work across multiple lines.

edited Dec 28 '11 at 21:10

answered Dec 28 '11 at 20:35

npinti

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@gpojd: Yeah, I could do it like that as well. I guess that yours is another way of getting the job done. I have modified my answer. – npinti Dec 28 '11 at 21:10
@gpojd it will fail to match `A1B2C3` for instance – fge Dec 28 '11 at 21:17
@fge, his original answer was identical to what I suggested. I only replaced `[^\s]` with `\S` for clarity. – gpojd Dec 28 '11 at 21:19

fge · Answer 2 · 2011-12-29T01:49:14.290

Try and match (\S*(?:\d\S*)*) on your input. Again the normal* (special normal*)* pattern, with normal being \S (anything but a space character) and special being \d+ (one or more digits):

fg@erwin ~ $ perl -ne 'print "Match: -->$_<--\n" foreach m/(\S*(?:\d+\S*))/gm' <<EOF
> firstTime=12   secondTime=34 
> 429923<=firstRange                353534=>secondRange
> A12345alpha      B9876beta
> EOF
Match: -->firstTime=12<--
Match: -->secondTime=34<--
Match: -->429923<=firstRange<--
Match: -->353534=>secondRange<--
Match: -->A12345alpha<--
Match: -->B9876beta<--

Depending on the regex engine you use, you may even use possessive quantifiers all along, or an atomic group to accelerate matching.

And if you want a book --> http://regex.info

score 0 · Answer 3 · answered Dec 28 '11 at 22:27

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Here is a regex that will match each "word" containing the digit "2".

\S*?2\S*

Change the 2 to any digit sequence you wish to match. If you wish to match Words containing a 2, 5 or 7, then use a character class:

\S*?[257]\S*

answered Dec 28 '11 at 22:27

ridgerunner

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How to match all words that contain a given digit?

3 Answers3