How to move a image across the screen on Android

Question

How to move an image across the screen android?

Guys, im creating MoleMash game for My Coursework and I really need help!. I want to try to move a image (the mole) across the screen in different and random coordinates so that it can be touched by the user to get a score. I created the background which I made the image view. I have the mole, Is it another image view? or is it a Image button?

And how do I move this across to different parts of the screen for the user interact?

I would greatly appreciate your help!

score 2 · Accepted Answer · edited May 23 '17 at 12:01

2

For games development you need to learn how to use canvas and SurfaceView: How can I use the animation framework inside the canvas?

Using onTouch event listener you would compare the touch location with the location of your animated images...

edited May 23 '17 at 12:01

Community

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answered Jan 02 '12 at 11:20

Lumis

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You dont need SurfaceView if you're doing simple animation.In that case you do however need to know about Android's animation framework: http://developer.android.com/training/animation/index.html - another alternative is OpenGL - though you'll have to know about OpenGLSurface view in that case. – AgentKnopf May 09 '15 at 21:24

score 0 · Answer 2 · answered Nov 15 '16 at 10:39

Try this code,

declare following variables

private Random random=new Random();

private int screenwidth, screenhgt;

In onCreate():

screenwidth= getyourScreenWidth;

screenhgt=getyourscreenheight;

Pass your view to this method(In my case I animate textview.. you pass the imageview)

private void screenRandomAnimator(final TextView textView) {

    final AnimatorSet mAnimatorSet = new AnimatorSet();
    mAnimatorSet.playTogether(ObjectAnimator.ofFloat(textView, "x", (float) random.nextInt(screenwidth), (float) random.nextInt(screenwidth)),
            ObjectAnimator.ofFloat(textView, "y", (float) random.nextInt(screenhgt), (float) random.nextInt(screenhgt)), ObjectAnimator.ofFloat(textView, "rotation", 360)
        /*    ObjectAnimator.ofFloat(textView, "scaleX", 1, 0.8f, 1, 1.1f, 1), ObjectAnimator.ofFloat(textView, "scaleY",  1, 0.8f, 1, 1.1f, 1)*/);
    int Low = 1500;
    int High = 2500;
    int Result = random.nextInt(High - Low) + Low;
    mAnimatorSet.setDuration(Result);
    mAnimatorSet.start();
    mAnimatorSet.addListener(new Animator.AnimatorListener() {
        @Override
        public void onAnimationStart(Animator animation) {

        }

        @Override
        public void onAnimationEnd(Animator animation) {
            mAnimatorSet.playTogether(ObjectAnimator.ofFloat(textView, "x", textView.getX(), (float) random.nextInt(screenwidth)),
                    ObjectAnimator.ofFloat(textView, "y", textView.getY(), (float) random.nextInt(screenhgt)));
            int Low = 1500;
            int High = 2500;
            int Result = random.nextInt(High - Low) + Low;
            mAnimatorSet.setDuration(Result);
            mAnimatorSet.start();
        }

        @Override
        public void onAnimationCancel(Animator animation) {

        }

        @Override
        public void onAnimationRepeat(Animator animation) {

        }
    });
}

score 0 · Answer 3 · edited May 23 '17 at 12:30

The mole would be an image button so it could be clicked, but to make it move you would have to use animation. Keep in mind that I am a beginner in Android animation as well :). You would probably use TranslateAnimation and set the x and y in the parameters to random variables, the duration could be when a time/counter variable reaches a certain point after the game has started. This post has more information on animation: How to move an image from left to right in android.

How to move a image across the screen on Android

3 Answers3

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