How to validate xml with dtd using java?

Question

I have following xml file:

<?xml version = "1.0" ?>
<Employee>
    <Emp_Id>E-001</Emp_Id>
    <Emp_Name>Vinod</Emp_Name>
    <Emp_E-mail>Vinod1@yahoo.com</Emp_E-mail>
</Employee>

I have following dtd file:

<!ELEMENT Employee (Emp_Id, Emp_Name, Emp_E-mail)>
<!ELEMENT Emp_Id (#PCDATA)>
<!ELEMENT Emp_Name (#PCDATA)>
<!ELEMENT Emp_E-mail (#PCDATA)>

I want to validate this xml file with above dtd using java.

Please, help thanks..:-)

Wayne · Accepted Answer · 2016-09-01T15:00:42.513

There are three things you should do:

Associate the source XML document with its DTD using a doctype declaration after the XML declaration:
```
<!DOCTYPE Employee SYSTEM "employee.dtd">
```
Note: The DOCTYPE root must match the root element in the source XML.
setValidating to true on the DocumentBuilderFactory
Provide an org.xml.sax.ErrorHandler instance to the DocumentBuilder using setErrorHandler

Here's a complete example:

DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance();
domFactory.setValidating(true);
DocumentBuilder builder = domFactory.newDocumentBuilder();
builder.setErrorHandler(new ErrorHandler() {
    @Override
    public void error(SAXParseException exception) throws SAXException {
        // do something more useful in each of these handlers
        exception.printStackTrace();
    }
    @Override
    public void fatalError(SAXParseException exception) throws SAXException {
        exception.printStackTrace();
    }

    @Override
    public void warning(SAXParseException exception) throws SAXException {
        exception.printStackTrace();
    }
});
Document doc = builder.parse("employee.xml");

Source document:

<?xml version="1.0"?>
<!DOCTYPE Employee SYSTEM "employee.dtd">
<Employee>
    <Emp_Id> E-001</Emp_Id>
    <Emp_Name> Vinod </Emp_Name>
    <Emp_E-mail> Vinod1@yahoo.com </Emp_E-mail>
</Employee>

Thanks lwburk!! but I dont allow to change in original source xml file. — Sachin J, Jan 04 '12 at 04:41
@SachinJ - read the file into memory, insert the DOCTYPE line, have the builder parse the XML string instead of a disk file. — Jesse Chisholm, Aug 11 '15 at 01:11
Sorry for the question but... where should I set the DTD filepath of the file set as "SYSTEM"? — Tobia, May 05 '20 at 07:59

score 1 · Answer 2 · edited May 23 '17 at 12:18

1

You just need to read the files and report the exceptions, if any. Here is a SAX parser example you can rely upon.

In order to validate your XML and DTD you just need to setValidating:

    DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
    dbf.setValidating(true); // since the default value is false

Also declare the DTD usage in your XML file:

<?xml version="1.0"?>
<!DOCTYPE Employee SYSTEM "employee.dtd">
<Employee>

edited May 23 '17 at 12:18

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answered Jan 02 '12 at 10:21

Costis Aivalis

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*Document root element "Employee", must match DOCTYPE root "employee".* – Wayne Jan 03 '12 at 19:37

How to validate xml with dtd using java?

2 Answers2

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